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3 years ago

3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l)

1 answer:

8 0

Mole ratio:

3 Cu(s) + 8 HNO₃(aq) = 3 Cu(NO₃)₂(s) + 2 NO(g) + 4 H₂O(l)

3 moles Cu(NO₃)₂ ----------------- 4 moles H₂O
3.3 moles Cu(NO₃)₂ ---------------- ??

moles H₂O = 3.3 x 4 / 3

moles H₂O = 13.2 / 3

=> 4.4 moles of H₂O

Answer C

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What is the numerical value for Q for this reaction? Remember to always express your answer to correct number of significant fig

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The reaction is not at equilibrium because Q >P hence the reaction moves towards the left hand side.

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The equilibrium constant is a figure that tells us the extent to which the reactants have been converted to products in a reaction.

Now we have the reaction; PCl3(g) + Cl2(g) ⇄ PCl5(g) hence we can write;

Q = [PCl5]/[PCl3] [Cl2]

Q = 0.39/0.21 * 0.41

Q = 4.5

The reaction is not at equilibrium because Q >P hence the reaction moves towards the left hand side.

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2 years ago

What is the chemical formula of the compound that forms when sodium and chloride combine?

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NaCI this wht forms when sodium and choride combine

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3 years ago

Why do scientists use the scientific method?

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Answer:

Scientists use the scientific method because it is evidence-based, standardized and objective in conducting experiments. The scientific method allows scientists to stick to facts and to avoid the influence of preconceived notions and personal biases in research processes, improving the credibility of research findings.

Explanation:

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3 years ago

Consider the following reaction. What is the conjugate base of CH3COOH

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According to Bronsted-Lowry theory of acids and bases, an acid is proton donor and a base is proton acceptor. When an acid loses the proton, it forms the conjugate base of the acid. Similarly when a base accepts a proton, it forms the conjugate acid if that base. A conjugate acid base pair differs by a single proton.

Given the weak acid $CH_{3}COOH$ . It can lose a proton to form the conjugate base.

$CH_{3}COOH(aq)-->CH_{3}COO^{-}(aq)+H^{+}(aq)$

Therefore, the conjugate base of $CH_{3}COOH$ is $CH_{3}COO^{-}$ .

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4 years ago

Read 2 more answers

The solubility of in water at a certain temperature is 35.7 g /100. g . Suppose that you have 330.0 g of . What is the minimum v

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The question is incomplete, here is the complete question:

The solubility of substance X in water at a certain temperature is 35.7 g /100. g. Suppose that you have 330.0 g of substance X. What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)

Answer: The minimum volume of water that would be needed is 940.17 mL

Explanation:

We are given:

Solubility of substance X in water = 35.1 g/100 g

This means that 35.1 grams of substance X is dissolved in 100 grams of water

Applying unitary method:

If 35.1 grams of substance X is dissolved in 100 grams of water

So, 330.0 grams of substance X will be dissolved in = $\frac{100}{35.1}\times 330=940.17g$ of water

To calculate the volume of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Mass of water = 940.17 g

Putting values in above equation, we get:

$1g/mL=\frac{940.17g}{\text{Volume of water}}\\\\\text{Volume of water}=\frac{940.17g}{1g/mL}=940.17mL$

Hence, the minimum volume of water that would be needed is 940.17 mL

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4 years ago