Answer:
Side of the square paper = 21 inches
Step-by-step explanation:
Let the square paper is having measure of each side = a inches
Esther cut this square piece into two pieces.
Let the other side of one rectangle piece = x inches
Perimeter of this piece = 2(a + x) inches
Similarly dimensions of the other rectangular piece will be = a inches × (a - x) inches
Perimeter of this piece = 2[a + (a - x)]
Since both the rectangular pieces have the same perimeter = 63
So, 2(a + x) = 2[a + (a - x)] = 63
2(a + x) = 2(2x - x)
a + x = 2a - x
2a - a = 2x
a = 2x
x = 
Therefore, Perimeter = 2(a + x) = 2(a +
) = 63
= 63
3a = 63
a = 21
Therefore, measure of the sides of the square is 21 inches.
Answer:
0.03 = 3%
0.18 = 18%
23/25 = 92%
Step-by-step explanation:
Answer:
Step-by-step explanation:
The segment addition theorem tells you ...
CD +DE = CE
x^2 +12x = 32 -2x
Subtract the right side to put this in standard form.
x^2 +14x -32 = 0
(x +16)(x -2) = 0
x = -16 or 2
In order for DE to have a positive length, we must have x > 0. So ...
CD = x^2 = 2^2 = 4
DE = 12x = 12(2) = 24
CE = 32 -2x = 32 -2(2) = 28
This is the correct answer is