The base of the right triangle drawn in the regular octagon measures 0.7 cm.
2 answers:
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Answer:
The number of students in the school band = 70
40% of students in the school band are sixth graders.
20% of students in the school band are seventh graders.
We have to find the number of band members that are sixth graders.
The number of sixth graders in school band are:
Therefore, there are 28 band members that are sixth graders.
Answer:
<u>Graph of the equation y = 2/5x - 1</u>
Please check the attached graph of the equation where:
The point (0, -1) represents the y-intercept, it is the point where the line crosses the y-axis.
The point (2.5, 0) represents the x-intercept, it is the point where the line crosses the x-axis.
Step-by-step explanation:
Given the equation
y = 2/5x - 1
<u>Determining the y-intercept:</u>
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
As the equation is given such as
y = 2/5x - 1
substitute x = 0
y = 2/5(0) - 1
y = 0 - 1
y = -1
so the ordered pair (0, -1) represents the y-intercept.
Thus, the y-intercept is: -1
<u>Determining the x-intercept:</u>
We know that the value of the x-intercept can be determined by setting x = y and determining the corresponding value of x.
As the equation is given such as
y = 2/5x - 1
substitute y = 0
0 = 2/5x - 1
2/5x = 1
x = 5/2
x = 2.5
so the ordered pair (2.5, 0) represents the x-intercept.
<u>Graph of the equation y = 2/5x - 1</u>
Please check the attached graph of the equation where:
The point (0, -1) represents the y-intercept, it is the point where the line crosses the y-axis.
The point (2.5, 0) represents the x-intercept, it is the point where the line crosses the x-axis.
Answer:
301.44 mm
Step-by-step explanation:
Diameter of the inside ring of a packing tape = 80 mm
The tape surrounding the ring is 8 mm beyond the ring which means the diameter of the ring including the surrounding will be:
80 + 8 + 8 = 96 mm
and its radius will be = 96/2 = 48.
To find the distance around the outer edge of the tape, we need to calculate the circumference for the ring with the tape on it.
<em>Circumference = </em>
Circumference = 2 x 3.14 x 48 = 301.44 mm
Therefore, the distance around the outer edge of the tape is 301.44 mm.