Answer:
63
Step-by-step explanation:
so y/3 - 9 = 12, add 9 on both sides and you get y/3 = 21. Then you multiply both sides by 3, y/3 * 3, the 3's cancel out, 21 * 3 = 63. You get y = 63
So basically just do + 9 on both sides then *3 on both sides (do it step by step)
F twice the 1st number minus 3 times the second number is 26<span>, </span>find both<span> ... </span>Twice the first number<span> is eleven more than </span>the sum<span> of the other </span>two numbers<span>.</span>
Answer:
B. 8.
D. log2 256.
Step-by-step explanation:
Generally:
loga b + loga b
= loga b^2.
Therefore log2 16 + log2 16
= log2 16^2
= log2 256.
From the above:
256 = 2^x where x is the log.
Now 2^8 = 256 so the original log2 16 + log2 16 = 8.
Given that the point (12,-5) which takes the form (x,y), This implies that:
opposite=-5
adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
c^2=a^2+b^2
plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13
Answer is option . D