Work in reverse.
45 + 15= 60. 60/2= 30. 30 + x = 47.
So, x= 47-30.
x= 17.
Answer:
-1
you use the given functions to set up and simplify f(2)
Answer:
A) JK and LM will be parallel to each other.
Step-by-step explanation:
On reflection on 
line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate
Points on line EF
On reflection of this line on the new points we get for line JK are
Points on line GH
On reflection on y=x line the new points we get for line LM are
Slope of line JK
Slope of line LM
For two line to be parallel, their slopes will be same.
Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Sin 45° = opposite side / hypotenuse
1/2 = 8/h
h = 16
2)6/12 = 1/2
1/2 = sin 45°
6√3/12 = √3/2
√3/2 = cos 30°
Sum of angles of triangle = 180°
The 3rd angle = 180 - (45 + 30) = 180 - 75 = 105°
Angles = 30° , 45° , 105°
