Marisol wants to determine how many students plan to attend the girls varsity basketball game . Find her mistake and correct it

Write the measurements of Sides AB, BC, and CD of the correct net.

scZoUnD [109]

AB- 3in.
BC- 5in.
CD- 7.2in.

sorry i don't really have an explanation I just looked at the picture and i guess imagined it in my head? lol sorry but here are the answers I hope that helps at least a little bit :))

8 0

2 years ago

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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

3 0

3 years ago

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Help me answer this.. plz

Fudgin [204]

Answer:

2 $\frac{1}{30}$

Step-by-step explanation:

First thing you gotta do is find the common denominator.

Do this by listing factors of the denominators:

5- 5, 10, 15, 20, 25, 30

6- 6, 12, 18, 24, 30, 36

5 and 6 both have 30 in common so that's the new denominator for all 3 of the terms.

What you do to the bottom you must do to the top.

Since you multiply 5 by 6 to get 30, you must multiply 2 and 4 by 6 as well.

Since you multiply 6 by 5 to get 30, then multiply 5 by 5 as well.

The new equation is:

$\frac{12}{30}$ + $\frac{25}{30}$ + $\frac{24}{30}$ =

Now add the numerators together

The solution is $\frac{61}{30}$ . Now simplify. 61 is prime, so you cannot change the fraction How many times does 30 go into 61? Two times. This gives us 2 $\frac{1}{30}$ .