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lozanna [386]
3 years ago
6

4. In a chromatography experiment, a student calculated that the solvent front was 6.8 cm above the starting line. Arginine trav

eled a distance of 4.9 cm and glycine traveled 3.4 cm. What Rf values would the student calculate for arginine and glycine
Chemistry
1 answer:
ziro4ka [17]3 years ago
3 0

Answer: 0.72 AND 0.5 RESPECTIVELY/.

Explanation:

The Rf value is defined as the ratio of the distance moved by the solute (i.e. the dye or pigment under observation) and the distance moved by the the solvent ie the migration of the solvent along the paper, where both distances are measured from point where the sample is first spotted on the paper.

Rf  value= (migration distance of substance)/(migration distance of solvent front)

or

Rf  value=Distance from Baseline travelled by Solute /Distance from Baseline travelled by Solvent (Solvent Front)

For Arginine Rf = (4.9 cm)/(6.8 cm) = 0.72

For glycine Rf = (3.4 cm)/(6.8 cm) = 0.5

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Answer:

a c e

Explanation:

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3 years ago
What is the theoretical yield of waffles if you have 6 cups of flour, 9 eggs and 2 tbs of oil?
Yanka [14]

Answer:

8 waffles

Explanation:

First, find the limiting reagent.  Divide the amount you have by the amount that is needed.  The smallest number is the limiting reagent.  <u>For this problem, the limiting reagent is oil.</u>

6 cups of flour/2 cups of flour = 3

9 eggs/3 eggs = 3             2 tbsp of oil/1 tbsp of oil = 2

This means that we can double the recipe since we have enough of each ingredient to make two batches.  Multiply the entire equation by 2.  This should give you   4 cups of flour  +  6 eggs  +  2 tbsp of oil  ==>  8 waffles.

<u>You should theoretically get 8 waffles.</u>

8 0
3 years ago
A hot piece of copper was dropped into 155 g of water at 23.6 °C and 2,100 J of energy was transferred to the water. What is the
BlackZzzverrR [31]

Answer:

26.8 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 155 g
  • Energy transferred to the water (Q): 2100 J
  • Initial temperature of the water (T₂): 23.6 °C
  • Final temperature of the water (T₁): ?
  • Specific heat of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C

5 0
3 years ago
In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an ex
Kay [80]

The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and $HCl$

  NaOH (aq) + HCl (aq) → NaCl(aq) + $H_2O (l)$

The above equation tells us that $1 \text{mole}$ of $NaOH$ reacts with $1 \text{mole}$ of $HCl$.

So at the equivalence point, the moles of NaOH added = moles of $HCl$present.

If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$  mole/L

The volume of NaOH added up to the color change = $V_2 \text{  and conc of NaOH = M}_2$ mole/L

Moles of $HCl$ taken = $V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$  moles.

The color change will occur when the moles of NaOH added is equal to the moles of $HCl$ taken.

Thus when $V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$

or   when    $V_1M_1 = V_2M_2$

or $V_2=\frac{V_1M_1}{M_2}$  mL of NaOH added, we observe the color change.

Where $V_1, M_1$ are the volume and molarity of the $HCl$ taken.

$M_2$ is the molarity of NaOH added.

When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$, then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$)

7 0
3 years ago
What is the purpose of stirring a solution while it is being heated?.
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Stirring and agitating chemical reactions is desirable and stirring reflux systems or any system under heating is necessary to a distribute the heat evenly throughout the system and b) to prevent splashing and boilovers.
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