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avanturin [10]
3 years ago
15

What is the molar mass of this hydrate?

Chemistry
1 answer:
Irina18 [472]3 years ago
6 0
Please provide the hydrate
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Enthalpy of <br><br> CH4(g) + 2NO2(g) -&gt; N2(g) + CO2(g) + 2H2O(l)
stira [4]

Answer:

-177.9 kJ.

Explanation:

Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.

5 0
2 years ago
Which expression is equal to the number of grams in 2.43 kilograms
KiRa [710]
1 kg = 1000g
2.43 kg *1000g/1kg = 2430 g
3 0
3 years ago
Show your work with good use of units, rounding, and significant figures. [Hint: it is good practice to show the value of your a
mel-nik [20]

Heat required : 4.8 kJ

<h3>Further explanation </h3>

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

The heat needed to raise the temperature

Q = m . c . Δt

1. heat to raise temperature from -20 °C to 0 °C

\tt Q=10\times 2.09\times (0-(-20)=418~J

2. phase change(ice to water)

\tt Q=10\times 333=3330~J

3. heat to raise temperature from 0 °C to 25 °C

\tt Q=10\times 4.18\times (25-0)=1045~J

\tt Q~tot=418+3330+1045=4793~J\rightarrow rounding~and~2~sig~figs=4.8~kJ

3 0
2 years ago
The following substances dissolve when added to water. Classify the substances according to the strongest solute-solvent interac
Norma-Jean [14]

Answer:

CuCl2-Ion-dipole forces

CuSO4-Ion-dipole forces

NH3-Dipole-dipole forces

CH3OH-Dipole-dipole forces

Explanation:

Water consists of a dipole. The water molecule contains a positive end and a negative end. The positive ion attracts the negative dipole of water while the positive dipole in water interacts with the negative ion of an ionic substance. This explains the dissolution of ionic substances in water.

Copper II chloride and copper sulphate are ionic substances hence they dissolve by the mechanism described above.

Molecules consisting of dipoles dissolves by interaction of the molecule's dipoles with the dipoles in water. For example, methanol interacts with water through hydrogen bonding which is involves molecular dipoles

3 0
2 years ago
This nonmetal is in the same group as lead.<br><br> What is the element
Andreyy89
Lead<span> (/lɛd/) is a chemical </span>element<span> in the carbon </span>group<span> with symbol Pb (from Latin: plumbum) and atomic </span>number<span> 82. 

~ I don't know if this will help, but I hope it does. ~</span>
5 0
3 years ago
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