How much work is done on an object if 6 newtons of force are applied to the object and it moves 3 meters?
1 answer:
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Use the law of sine
note that:
sin(42)/4.8=sin(80)/PQ
PQ=4.8sin(80)/sin(42)
PQ≈7.1
note that:
sin(42)/4.8=sin(80)/PQ
PQ=4.8sin(80)/sin(42)
PQ≈7.1
