Answer:
ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Step-by-step explanation:
It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.
If a figure is dilated then preimage and image are similar.
If scale factor is between 0 to 1, then preimage is reduction of image.
If scale factor is more that 1, then preimage is enlargement of image.
If scale factor is 1, then preimage is congruent to the image.
We know that

So,

Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Answer:
she need to buy 9 packs
Step-by-step explanation:
C = 2πr
= 2·3.14·14
= 87.92 m
she need to buy 9 packs
Answer:
Option (3)
Step-by-step explanation:
From the figure attached,
AB and CD are two chords intersecting at O.
m∠AOD = 37°
m∠AOC + m∠AOD = 180° [Since these angles are supplementary angles]
m∠AOC = 180° - 37°
= 143°
By the theorem of intersecting chords,
Measure of angle formed is the half of the sum of measures of the arcs intercepted by the angle and vertical angle.
m∠AOC = 
143° = ![\frac{1}{2}[(x+5)+(x-5)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28x%2B5%29%2B%28x-5%29%5D)
143° = x
Therefore, Option (3) will be the answer.
Answer:
I would say B
Step-by-step explanation: