Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.
Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,
Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.
Given: 1m squared floor tiles costs $3. So,
Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.
Therefore, the combined total cost of tiles and paint is $924.
Lets say the base is x and the height is y. The new base would be 1.2x and the new height would be 1.3y
Area of a triangle is base times height divided by 2:
1.2x*1.3y/2 = (1.2*1.3 + x*y)/2 = 1.56xy/2 = 0.78xy = 78% of xy
But a normal area would be 50% of xy
78% - 50% = 38%
ANSWER: 38% increase
Slope = (y2-y1)/(x2 - x1)
Slope = (9 - 6)/(-3- (-9)) = 3/6 = 1/2
Answer: 1/2
Answer:
The answer is x=1
Step-by-step explanation:
-4(3x+6)+6=-30
-12x-24+6=-30
-12x-18=-30
-12x-18+18=-30+18
-12x=-12
-12x/-12=-12/-12
x=1
With what ??? I don’t see nothing
