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Yuliya22 [10]
4 years ago
8

What is the name of the compound with a formula ch3ch2ch2ch3?

Chemistry
1 answer:
Charra [1.4K]4 years ago
5 0
The name of the compound with the formula ch3ch2ch2ch3 is butane. 
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The component that runs the circuit is C the wire
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3 years ago
Diferencia entre red trofica y cadena trófica
Angelina_Jolie [31]

Answer:

Una cadena alimentaria es una secuencia lineal de organismos a través de la cual los nutrientes y la energía pasan de un organismo a otro mediante consumo. ... Las redes tróficas consisten de varias cadenas alimentarias interconectadas y son una representación más realista de las relaciones de consumo en los ecosistemas

Explanation:

A food chain is a linear sequence of organisms through which nutrients and energy pass from one organism to another by consumption. ... Food webs consist of several interconnected food chains and are a more realistic representation of consumption relationships in ecosystems

6 0
3 years ago
14 H+ + 6 Fe2+ + Cr2O72- . 2 Cr3+ + 6 Fe3+ + 7 H2O This reaction is used in the
chubhunter [2.5K]

Answer:

Option A 0.5424 M

Explanation:

To do this, let's write the reaction again and see the mole ratio:

14H⁺ + 6Fe²⁺ + Cr₂O₇⁻ ---------> 2Cr³⁺ + 6Fe³⁺ + 7H₂O

According to this reaction, we have a mole ratio between the dicromate and iron of 1:6. In other words, 6 moles of dicromate reacts with only 1 mole of iron, therefore we can use the following expression:

nFe = 6 * nCr₂O₇

This is a REDOX reaction, where Iron is being oxidized while cromium is being reduced. Now, we have the concentrations and volume, let's express the moles in function of concentration and volume:

M₁V₁ = 6M₂V₂

Replacing the given data above and solving for concentration of iron (M₁)

M₁ = 6 * 45.20 * 0.1 / 50

M₁ = 0.5424 M

This is the concentration of the iron solution

3 0
3 years ago
How would you prepare 500.0 mL of a 2.00 mol/L solution of HCI from a concentrated solution of 12.0 mol/L?
JulsSmile [24]

c(desired)*V(final) = c(conc)*V(add)

V(add) = c(desired)*V(final) / c(conc) = 2*0.5 / 12 = 0.0833 cm3 = 83.3 mL of 12 M HCl needs to be added.

First add the distilled water: 416,7 mL.

Then add the conc. HCL by using an autopipette 8 times with 10.0 mL, 1 time with 3.0 mL and then 1 time with 300 microliter .

8 0
3 years ago
What is the molality of a solution that contains 1.34 moles of NaCl in 2.47 kg of solvent
dsp73

The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

         \text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

Hence, \text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}

Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

8 0
4 years ago
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