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Scrat [10]
3 years ago
11

A substance with a pH less than 7

Chemistry
2 answers:
kari74 [83]3 years ago
8 0

Answer:

An acid

Explanation:

On the pH scale, 7 is neutral, or the pH of pure water. Any substance with a pH of lower than 7 is an acid, while anything with a pH of higher than 7 is a base. The pH scale is measured logarithmically, meaning that each step up is 10 times more powerfully either base or acidic, whichever side it was on.

PolarNik [594]3 years ago
3 0
Coffe, wine, orange juice, gastric juice.
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Sometimes you are given a measured amount of two or more reactants and asked how much product can be formed. Explain what steps
Westkost [7]

Explanation:

To solve this problem, follow these steps;

  • Obtain a balanced equation of the reaction and familiarize with the reactants and products.
  • Find the number of moles of the reacting species since they are the known matter in terms of quantity.
  • From the number of moles, determine the limiting reactant.
  • The limiting reactant is the one given in short supply.
  • Such reactant determines the extent of the reaction.
  • Compare the moles of this specie to that of the products using the balanced equation.
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learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

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Pick 3 objects around your room and write 2 observations and 2 interpretations about object . BTW I just moved I only have a bed
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3 years ago
If a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay, what will be the new element?
Charra [1.4K]

Answer:

The new element will be thorium-226 (²²⁶Th).

Explanation:

The beta decay is given by:

^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}

Where:

A: is the mass number

Z: is the number of protons  

β⁻: is a beta particle = electron

\bar{\nu_{e}}: is an antineutrino

The neutral atom has 88 electrons, so:

e^{-} = 88 = Z

Hence the element is radium (Ra), it has A = 226.

If Ra undergoes 2 rounds of beta minus decay, we have:

^{226}_{88}Ra \rightarrow ^{226}_{89}Ac + \beta^{-} + \bar{\nu_{e}}    

^{226}_{89}Ac \rightarrow ^{226}_{90}Th + \beta^{-} + \bar{\nu_{e}}

Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).

I hope it helps you!    

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Where is the diagram then I will be able to answer
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Members of which group easily lose an electron to form a +1 cation?
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The alkali metals, which occupy group 1 of the periodic table. This is because the valence shells of these elements have only 1 electron, so easily form an ionic bond with a non-metal compound by donating this. A cation is formed by this donation, since there is one fewer electron orbiting the nucleus than there is in the atomic form - conversely an anion is formed when an atom gains an extra electron to become negatively charged.
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