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professor190 [17]
3 years ago
8

Ethyl alcohol evaporates faster then water, why?​

Chemistry
1 answer:
nadezda [96]3 years ago
8 0

Explanation:

as alcohol evaporates at much faster rate compared with water due to its lower boiling temperature (82 compared to 100 degree Celsius), it is able to carry away more heat from the skin. this means for a given amount of time much more alcohol evaporates than water.

hope it helps you

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Can You Tell?<br> Pepsinogen is released in the stomach. Why can't it digest stomach walls?
miv72 [106K]

Answer:

Specific cells within the gastric lining, known as chief cells, release pepsin in an inactive form, or zymogen form, called pepsinogen. By doing so, the stomach prevents the auto-digestion of protective proteins in the lining of the digestive tract.

Explanation:

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5 0
3 years ago
H. Nitrogen gas and hydrogen gas combine to produce ammonia gas (NH3).
DedPeter [7]

Answer:

<u>27.3 L</u>

Explanation:

<u>Reaction</u>

  • N₂ (g) + 3H₂ (g) ⇒ 2NH₃ (g)
  • This is the basic reaction at STP

<u>Solving</u>

  • 10 g N₂ x 1 mol NH₃/28 g N₂ x 3 mol H₂/1 mole N₂
  • ⇒ 1.07 mol H₂

  • V = nRT/P [From Ideal Gas Equation]
  • V = 1.07 x 62.36 x 298 K / 735
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4 0
3 years ago
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
3 years ago
Who wants to be marked as brainlyest
Serjik [45]

Answer:

Ummm...?

Explanation:

5 0
3 years ago
A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
4 years ago
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