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Simora [160]
3 years ago
15

You have a beaker of water that potentially has Ag+ ions and Ba+ ions (it could have both, one of them, or none of them). How wo

uld you design an experiment (flow chart or procedure steps) that will determine which (if any) of these ions are in your water?
Chemistry
1 answer:
xenn [34]3 years ago
6 0

Answer:

See explanation

Explanation:

Qualitative analysis in chemistry is a method used to determine the ions present in a solution chiefly by means of chemical reactions.

In this case, I suspect the presence of silver ions and/or barium ions. The first step is to add dilute HCl. This will lead to the precipitation of the silver ion as AgCl. If a white precipitate is formed upon addition of HCl then Ag^+ is present in the solution.

Secondly, I add a carbonate such as NH4CO3(aq). This will cause the barium ions to become precipitated as barium carbonate. Hence, the formation of a white precipitate when NH4CO3(aq) is added to the solution indicates the presence of barium ion in the solution.

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Please help me with this question!! read the photo
pishuonlain [190]

There are 1.92 × 10^23 atoms Mo in the cylinder.

<em>Step 1</em>. Calculate the <em>mass of the cylinder </em>

Mass = 22.0 mL × (8.20 g/1 mL) = 180.4 g

<em>Step 2</em>. Calculate the<em> mass of Mo </em>

Mass of Mo = 180.4 g alloy × (17.0 g Mo/100 g alloy) = 30.67 g Mo

<em>Step 3</em>. Convert <em>grams of Mo</em> to <em>moles of Mo </em>

Moles of Mo = 30.67 g Mo × (1 mol Mo/95.95 g Mo) = 0.3196 mol Mo

<em>Step 4</em>. Convert <em>moles of M</em>o to <em>atoms of Mo </em>

Atoms of Mo = 0.3196 mol Mo × (6.022 × 10^2<em>3</em> atoms Mo)/(1 mol Mo)

= 1.92 × 10^23 atoms Mo

7 0
3 years ago
Four cars travel at the same speed down a road. Their mass and kinetic energy are shown in the graph,
Alex777 [14]

Answer:B

Explanation:

3 0
2 years ago
Explain how you were able to use your knowledge of how different types of blood react with anti A, anti B, and anti Rh antibodie
dybincka [34]

Depending upon the clumping reaction with anti A , anti B and anti Rh antibodies the blood types are determined.

Explanation:

Agglutination (clumping) will occur when blood that contains the particular antigen is mixed with the particular antibody.

A+ have Agglutination with Anti-A ,Anti-Rh and No agglutination with Anti-B.

A- have Agglutination with Anti-A and No agglutination with Anti-B and Anti-Rh.

B+ have Agglutination with Anti-B Anti-Rh and No agglutination with Anti-A.

B- have Agglutination with Anti-B and No agglutination with Anti-B and Anti-Rh.

Rh+ have Agglutination with Anti-A and Anti-Rh and No agglutination with Anti-B.

Rh- have No Agglutination with Anti-A and Anti-B and Anti-Rh.

3 0
3 years ago
When compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet,
kati45 [8]

Answer:

attached here is the diagram of the solution

Explanation:

4 0
4 years ago
Identify the element: 6 energy level, metallic, 82 election
Lady bird [3.3K]

<u>Answer</u>:-

Name of element = Lead

Symbol ♾ of Lead = Pb

Atomic no. = 82

Atomic mass = 207.2 amu

No. of protons = 82

No. of electrons = 82

Yes, lead(Pb) is a metallic element and certainly it has 6 electron shells which means 6 energy level.

If you find anything unclear you can ask me...

6 0
3 years ago
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