Mass of sodium thiosulfate
is 110. g
Volume of the solution is 350. mL
Calculating the moles of sodium thiosulfate:
= 0.696 mol
Converting the volume of solution to L:

Finding out the concentration of solution in molarity:

Balanced equation : C. CH₄ + 4Cl₂⇒ CCl₄+ 4HCl
<h3>Further explanation </h3>
Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product
3. Select the coefficient of the substance with the most complex chemical formula equal to 1
Reaction
CH₄ + Cl₂⇒ CCl₄+ HCl
aCH₄ + bCl₂⇒ CCl₄+ cHCl
C, left=a, right=1⇒a=1
H, left=4a, right=c⇒4a=c⇒4.1=c⇒c=4
Cl, left=2b, right=4+c⇒2b=4+c⇒2b=4+4⇒2b=8⇒b=4
The equation becomes :
CH₄ + 4Cl₂⇒ CCl₄+ 4HCl
<span>A submerged object displaces a volume of liquid equal to the volume of the object. One milliliter (1 mL) of water has a volume of 1 cubic centimeter (1cm3).</span>
Answer:
435.38 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 3.25 mole
Initial volume (V₁) = 100 L
Final mole (n₂) = 14.15 mole
Final volume (V₂) =?
The final volume occupied by the gas can be obtained as follow:
V₁/n₁ = V₂/n₂
100 / 3.25 = V₂ / 14.15
Cross multiply
3.25 × V₂ = 100 × 14.15
3.25 × V₂ = 1415
Divide both side by 3.25
V₂ = 1415 / 3.25
V₂ = 435.38 L
Thus, the final volume of the gas is 435.38 L