3 years ago

I need it ASAP;

Mathematics

1 answer:

vladimir1956 [14]3 years ago

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Answer:

Step-by-step explanation:

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Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)

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$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3$

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3 years ago

An experiment consists of drawing a marble out of a bag, observing the color, and then placing it back in the bag. Suppose the e

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The experimental data suggest that

$\mathbb P(\text{red})\approx\dfrac{38}{75}$
$\mathbb P(\text{blue})\approx\dfrac{23}{75}$
$\mathbb P(\text{green})\approx\dfrac{11}{75}$
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Because the marble is replaced after being drawn, and so the number of marbles of a given color remains the same, the event of drawing any given color is independent of what was drawn before. So

$\mathbb P(\text{2 consecutive yellows})\approx\dfrac3{75}\cdot\dfrac3{75}=\dfrac1{625}$

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4 years ago

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I think it is 64 cause i multiplied

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4 years ago

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6.8,6.827,6.86,6.9

1.2,1.203,12.03, 12.301,12.31

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