Which phase(s) would experience a decrease in the rate of dissolution with an increase in temperature?
2 answers:
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Answer: The ion formed after the reduction of bromine is
Explanation:
The electronic configuration of Sodium (Na) =
The electronic configuration of Bromine (Br) =
From the above configurations, Sodium ion will loose 1 electron in order to gain stable electronic configuration and that electron is accepted by the Bromine atom because it is 1 electron short of the stable electronic configuration.
(oxidation reaction)
(Reduction reaction)
Bromine atom is reduced to form
Reduction reactions are the reactions in which the element gain electrons.
Oxidation reactions are the reactions in which the element looses its electrons.
The question is incomplete, here is the complete question:
Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in
The image is attached below.
<u>Answer:</u> The density of CsI is
<u>Explanation:</u>
To calculate the density of metal, we use the equation:
where,
= density
Z = number of atom in unit cell = 2 (BCC)
M = atomic mass of CsI = 259.8 g/mol
= Avogadro's number =
a = edge length of unit cell = (Conversion factor:
)
Putting values in above equation, we get:
Hence, the density of CsI is
