Number of O atoms : 24
<h3>Further explanation</h3>
Given
C₆H₁₂O₆ compound
Required
Number of atoms
Solution
A molecular formula shows the number of atomic elements in compound.
The empirical formula is the smallest comparison of the atoms
Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.
The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules
So number of O atoms :
= 4 x 6 = 24 atoms
There are 11 Carbon atoms in the compound.
<u>Solution:</u>
Carbon atom count is the ratio of the M peak to the M+1 peak.
Here M peak is 57.10% and M+1 peak is 6.83%. On applying the values in the formula we get,
Therefore, the number of Carbon atoms in the compound are 11.
Refer the image attached below for a better understanding of M peak and M+1 peak.
The heaviest ion that has the greatest m/z value is said to be the molecular ion peak in mass spectrum.
Answer:
The force that keeps the planets in orbit is gravity.
0.295 * 203 = 53.885
0.705 * 205 = 144.525
53.885 + 144.525 = 204.41
The relative atomic mass of Thallium is 204.41
2. Rubidium
3. Antimony
4. Ytterbium
5. Einsteinium
