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kkurt [141]
3 years ago
5

How would temperature changes in the atmosphere enough to melt Antarctic Ice affect the hydrosphere lithosphere and biosphere

Chemistry
2 answers:
vlada-n [284]3 years ago
4 0

This is possible because of pollution which creates global warming, which then affects the atmosphere then it melts the Antarctic ice

Dennis_Churaev [7]3 years ago
3 0
Ima wait till someone else answers

You might be interested in
Calculează masa zaharului si volumul apei necesare pentru prepararea 500g de soluție de zahăr cu partea de masa 20%
Sedbober [7]
T = 20 %  : 20 / 100 = 0.2

m1 = solute 

m2 = Solvent

T = m1 / m1 + m2

0.2 = 500 g / 500 g + m2

0.2 * ( 500 + m2 ) = 500

0.2 * 500 + 0.2 m2 = 500

100 + 0.2 m2 = 500

0.2 m2 = 500 - 100

0.2 m2 = 400

m2 = 400 / 0.2

m2 = 2000 g of water

hope this helps!



7 0
3 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
How would you prepare 3.5 L of a 0.9M solution of KCl?
Fudgin [204]
Calculate the mass of the solute <span>in the solution :

Molar mass KCl = </span><span>74.55 g/mol

m = Molarity * molar mass * volume

m = 0.9 * 74.55 * 3.5

m = 234.8325 g 

</span><span>To prepare 0.9 M KCl solution, weigh 234.8325 g of salt in an analytical balance, dissolve in a beaker, shortly after transfer with the help of a funnel of transfer to a volumetric flask of 100 cm</span>³<span> and complete with water up to the mark, then cover the balloon and finally shake the solution to mix

hope this helps!</span>
8 0
3 years ago
A chemist has a 3.25-mole sample of potassium (K) to use in an experiment. What is the mass of this sample?
s344n2d4d5 [400]
Hi!
• For this you want to convert moles to grams
• To do this you would simply multiple your moles times the atomic mass of potassium
3.25 x 39.098= 127.0685
• So your answer for this should be about 127.07 depending on how you need to round!
5 0
2 years ago
A ballerina weighs 103 lbs and is up on her toes with only 10.0 cm2 of her slippers in contact with the floor. What pressure is
Ahat [919]

Answer:

A

Explanation:

1 lb = .453 kg...so...103 x .453 = 46.72 kg  

you then multiply that by the force of gravity which is 9.8(m/s2)...so...  

46.72 x 9.8 = 458 newtons(kg x m/s^2), which is the force.  

pressure (in pascals) = Force(N) / Area (m2)  

we need to convert 10cm2 to m2 which = .001m^2  

458 / .001 = 458000 = 4.58 x 10^5 Pa

8 0
3 years ago
Read 2 more answers
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