Answer:
c = 1 , a = 2, b = 3
Step-by-step explanation:
Answer:
5 track practices
Step-by-step explanation:
So if he ran 8 miles in 4 track practices, he ran 2 miles in each.
So it would take 5 track practices to do it.
No because 6/6 is equivalent to 1 and 3/5 is less than 1. Hope this helps! :)
We are dealing here with a uniform distribution ranging from 0 to 30 minutes. We need to calculate the probability that the unreliable bus will arrive before the reliable one. This probability is the area under the uniform distribution "curve" from 0 to 10 minutes. This constitutes 1/3 of the entire unform distr. curve. So the probability that the unreliable bus will arrive before the reliable one is 1/3, or 0.33. The probability that it will arrive AFTER the reliable bus is 2/3, or 0.67.