From my research, the original system of equations contain the following equations:
<span>2x − y = −4
3x + 5y = 59
where obtained solution is x = 3
Among the choices, it is easier to substitute </span><span>3x + 5y = 59 with one of the choices to see if they yield the same solution set. From trial-and-error, the equation that can replace the original equation is " 13x = 39 ". Among the choices, it is the 4th choice.</span>
Let's plug in the variables one by one.
6g - 2h
plug in 5 for g and 4 for h
6(5) - 2(4)
multiply
30 - 8
subtract
→ 22
20g
plug in 2 for g
20(2)
multiply
40
2(g + 1)
plug in 10 for g
2(10 + 1)
add
2(11)
multiply
→ 22
4g + 5h
plug in 1 for g and 4 for h
4(1) + 5(4)
multiply
4 + 20
add
24
Therefore, the answers that have a value of 22 are 6g - 2h and 2(g + 1)
Answer:
- height: 9 chi 6 cun
- width: 2 chi 8 cun
Step-by-step explanation:
The factor-of-ten relationship between the different units means we can combine the numbers in decimal fashion. If 1 unit is 1 zhang, then 1 chi is 0.1 zhang and 1 cun is 0.01 zhang. Hence 6 chi 8 cun is 0.68 zhang.
Let x and y represent the width and height, respectively. In terms of zhang, we have ...
y - x = 0.68
x^2 +y^2 = 1^2
Substituting y = 0.68 +x into the second equation gives ...
x^2 + (x +0.68)^2 = 1
2x^2 +1.36x - 0.5376 = 0 . . . . . eliminate parentheses, subtract 1
Using the quadratic formula, we have ...
x = (-1.36 ±√(1.36^2 -4(2)(-0.5376)))/(2·2) = (-1.36 ±√6.1504)/4
x = 0.28 . . . . . the negative root is of no interest
y = 0.28 +0.68 = 0.96
In units of chi and cun, the dimensions are ...
height: 9 chi 6 cun
width: 2 chi 8 cun
Answer:
60 times
Step-by-step explanation:
The numbers are 1, 2, 3, 4, 5, 6
1, 3, and 5 are odd
therefore half the numbers are odd
therefore there is a 50% chance she will get an odd number
50% * 120 = 60
so the answer is 60
Answer:
Isolate one variable in one of the equations and substituting it into the other equation. *note* in example the first substitution is given to you
Step-by-step explanation:
For example:
-3x-4y=-2
y=2x-5
Substitute -4y with second equation
-3x-4(2x-5)=-2
PEMDAS
-3x-8x+20=-2
-11x+20=-2
Subtract 20 on both sides of the = sign
-11x=-22
Divide both sides
x=2
Plug that into the second equation
y=2(2)-5
y=4-5
y=-1
