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Bess [88]
3 years ago
14

Shopping at clothing world, jenna buys her children four shirts and three pairs of pants for 124.25. She returns the next day an

d buys three shirts and five pair of pants for 161.25. What is the price of each shirt and each pair of pants?
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

The cost of one shirt is 12.50 and cost of one pair of jeans is 24.75

Step-by-step explanation:

Let,

Cost of one shirt = x

Cost of pair of jeans = y

According to given statement;

4x+3y=124.25    Eqn 1

3x+5y=161.25     Eqn 2

Multiplying Eqn 1 by 3

3(4x+3y=124.25)\\12x+9y=372.75\ \ \ Eqn\ 3

Multiplying Eqn 2 by 4

4(3x+5y=161.25)\\12x+20y=645\ \ \ Eqn\ 4

Subtracting Eqn 3 from Eqn 4

(12x+20y)-(12x+9y)=645-372.75\\12x+20y-12x-9y=272.25\\11y=272.25

Dividing both sides by 11

\frac{11y}{11}=\frac{272.25}{11}\\y=24.75

Putting 24.75 in Eqn 1

4x+3(24.75)=124.25\\4x+74.25=124.25\\4x=124.25-74.25\\4x=50

Dividing both sides by 4

\frac{4x}{4}=\frac{50}{4}\\x=12.50

The cost of one shirt is 12.50 and cost of one pair of jeans is 24.75

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/2670657
  • brainly.com/question/2821386

#LearnwithBrainly

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Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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posledela

90° = complimentary

middle one = is neither

3rd one is supplementary

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