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Airida [17]
3 years ago
13

Please answer! This is my last tryyyy

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
5 0
Yes the problem is true and 56 is a solution
mezya [45]3 years ago
5 0

Answer: yea he is right

Step-by-step explanation:

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Find the equation of the line that<br> is parallel to y = 4x + 1 and<br> contains the point (1, 1).
n200080 [17]

Answer:

y=4x+1

answer= y=4x

Step-by-step explanation:

y=4x+1

1=4(1)+1

1=5

4 0
2 years ago
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Given that ∠A≅∠B , Evelia conjectured that ∠A and ∠B are acute angles.
eimsori [14]
45 and 45 is the answer
3 0
3 years ago
A rocket is launched from a height of 3m with an initial velocity of 15 m/s at what time will the rocket be 13m from the ground?
dem82 [27]
Not sure of my answer but, velocity=delta d/delta t. t=delta d/ velocity
—> t=(13-3)/15=>10/15=2/3s
4 0
2 years ago
Explain in words how to find the product of -4 (-1.5) using a number line.where do you end up
Ierofanga [76]

Answer:

To multiply two minus numbers they  will result as a positive number.

the product of any numbers when there is a negtive will always have 2 negtives invlved form three numbers including the answer.

-4 x -1.5 is the same as 4 x 1.5

the answer is  6

Three numbers like -1 x  4 will also be 2 numbers of negative.

= -4

We change this to -4 x 1.5 and shows the answer as -6

But the question had 2 negative numbers already and the answer is just positive 6.

8 0
3 years ago
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Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)
Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

This is equal to the left hand side.

Thus, it is verified.

5 0
2 years ago
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