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4 years ago

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A powerplant is emitting 80 g/s NO and has an effective stack height of 100 m. The windspeed is measured to be 4 m/s at a height

of 10 m. It is a clear summer day and the sun is located directly overhead. Find: a. Ground-level NO concentration 2 km directly downwind of the powerplant. b. Maximum NO concentration at the ground-level. c. Ground-level NO concentration 2 km downwind and 0.1 km off the downwind axis.

1 answer:

Elodia [21]4 years ago

6 0

Answer:

Explanation:

The step by step solution is in the attached file.

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An asphalt concrete mixture includes 94% aggregates by weight. The specific gravity of aggregate and asphalt are 2.7 and 1.0, re

riadik2000 [5.3K]

Answer:

The correct solution is "5.74%".

Explanation:

The given values are:

Gravity of aggregate,

$G_{agg}=2.7$

Gravity of asphalt,

$G_{asp}=1.0$

Asphalt concrete mixture,

$W_{agg}=0.94 \ W_m$

We know that,

$W_{asp}=W_m-W_{agg}$

$=0.06 \ W_m$

Now,

The theoretical specific gravity of mix,

⇒ $G_t=\frac{W_{agg}+W_{asp}}{\frac{W_{agg}}{G_{agg}} +\frac{W_{asp}}{G_{asp}} }$

By putting the values, we get

$=\frac{0.94 \ Wm+0.06 \ Wm}{\frac{0.94 \ Wm}{2.7} +\frac{0.06 \ Wm}{1} }$

$=2.45$

hence,

The percentage of voids will be:

⇒ %V = $\frac{G_t-G_m}{G_t}\times 100$

= $\frac{2.45-2.317}{2.45}\times 100$

= $\frac{0.133}{2.317}\times 100$

= $5.74$ (%)

8 0

3 years ago

At a high school science fair, Connor won first place for his replica of the Golden Gate Bridge. Connor liked the

PtichkaEL [24]

The correct answer is A. Earning a bachelor's degree in Civil Engineering from a four-year university, completing an internship, and seeking a job at a private firm.

Explanation:

In the U.S. and many countries, the best to start a career is to enroll in a formal educational program at a university or college. This helps students learn concepts, theories, methods, etc. they need for their profession. Moreover, a degree such as a bachelor's degree is required by employers. In this context, the first step for Connor is to earn a bachelor's degree in Civil Engineering.

Besides this, an internship is recommended after earning a degree because this is the way students can gain real-life work experience, which is considered positive by employers. This means the next step should be an internship.

Finally, Connor can seek a job to design bridges and other buildings because after the degree and internship he will have the experience and knowledge required by employers and by the job.

6 0

3 years ago

True or false: You can create a network with two computers.<br><br><br><br> Answer<br> True

coldgirl [10]

To create a computer network, you must have at least two computers. ... A protocol is a standard set of rules and procedures for the control of communications in a network. TRUE. Two computers using TCP/IP can communicate even if they are based on different hardware and software platforms. So your right :)

Hope this helps :)

7 0

3 years ago

Read 2 more answers

Water is the working fluid in an ideal Rankine cycle. Steam enters the turbine at 1400 lbf/in2 and 1000°F. The net power output

Alex17521 [72]

Answer:

(a) The mass flow rate of the steam is approximately 1.803×10⁶ lb/h

(b) The rate of heat transfer is approximately 2.52×10⁹ BTU/h

(c) The thermal efficiency is approximately 39.68%

(d) The mass flow rate of cooling water is approximately 9.478 × 10⁷ lb/h

Explanation:

(a) The parameters are;

T₁ = 1000 F, P₁ = 1400 psi

By using an online application, we have;

h₁ = 1494 BTU/lb = 3,475 kJ/kg

s₁ = 1.61 BTU/(lb·R) = 6.741 kJ/(kg·K)

Therefore, due to isentropic expansion from state 1 to state 2, we have;

s₁ = s₂ = 1.61 BTU/(lb·R)

P₂ = 2 psi

T₂ =

$s_f$ = 0.17498 BTU/(lb·R)

$h_{f2}$ = 94.02 BTU/(lb)

$h_g$ = 1116 BTU/lb

$s_g$ = 1.919 BTU/(lb·R)

We have;

x₂ = (1.61 - 0.17498)/(1.919 - 0.17498) ≈ 0.823

h₂ = $h_f$ + x₂×( $h_g$ -

P₃ = P₂ = 2 psi

h₃ = $h_{f2}$ = 94.02 BTU/(lb)

v₃ = 0.01605 ft³/lb

h₄ = h₃ + v₃ × (P₄ - P₃)

h₄ = 94.02 + 0.01605 × (1400 - 2) ×144/778 = 98.17 BTU/lb

The mass flow rate of the steam, $\dot m$ = $\dot W$ /((h₁ - h₂) - (h₄ - h₃)) = 1 * 10^9/((1494 -935.11) - (98.17 -94.02)) ≈ 1.803×10⁶ lb/h

$\dot m$ ≈ 1.803×10⁶ lb/h

The mass flow rate of the steam ≈ 1.803×10⁶ lb/h

(b)The rate of heat transfer, $\dot Q_{in}$ = $\dot m$ × (h₁ - h₄) = 1.803×10⁶×(1494 -98.17) ≈ 2.52×10⁹ BTU/h

$\dot Q_{in}$ ≈ 2.52×10⁹ BTU/h

(c) The thermal efficiency = $\dot W_{cyc}$ / $\dot Q_{in}$ = 1×10⁹/(2.52×10⁹) = 0.3968 ≈ 39.68%

The thermal efficiency ≈ 39.68%

(d) The mass flow rate of cooling water $\dot m_w$ = $\dot m$ (h₂- h₃)/( $c_w \Delta T$ )

$c_w$ = 1 BTU/(lb·°F)

$\dot m_w$ = 1.803×10⁶ (935.11- 94.02)/(1 * (76 - 60)) ≈ 9.478 × 10⁷ lb/h

$\dot m_w$ ≈ 9.478 × 10⁷ lb/h

The mass flow rate of cooling water ≈ 9.478 × 10⁷ lb/h.

5 0

3 years ago

In a foundry, metal castings are cooled by quenching in an oil bath. Typically, a casting weighting 20 kg and at a temperature o

Irina18 [472]

Answer:

4.18 J/KgK

Explanation:

Equilibrium point is reached when

m₁*c₁(T₁-T) = m₂*c₂(T -t₂)

m1 = 20

c1 = 0.5

T1 = 450

m2 = 150 kg

c2 = 2.6

T2 = 50

putting these values into the formula

20*0.5 (450-T) = 150*2.6(T - 50)

4500 - 10T = 390T<em> - 19500</em>

4500 + 19500 = 390T + 10T

24,000 = 400T

T = 24000/400

= 60⁰C

ΔSmetal = m1*c1In[t + 273]/[T1+273]

= 20*0.5 In (60+273)/450+273

= 10 ln(333/723)

= 10 * -0.7752

= -7.752

ΔS/oil =

m2*s2(60 + 273)/50 + 273)

= 150*2.6ln(333/323)

= 390 * 0.03048

= 11.88j/KgK

Δ<em>total = -7.7+11.8</em>

<em>= </em><em>4.18J/KgK</em>

this is the enthropy change

5 0

3 years ago