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2 years ago

At a high school science fair, Connor won first place for his replica of the Golden Gate Bridge. Connor liked the

Engineering

1 answer:

PtichkaEL [24]2 years ago

6 0

The correct answer is A. Earning a bachelor's degree in Civil Engineering from a four-year university, completing an internship, and seeking a job at a private firm.

Explanation:

In the U.S. and many countries, the best to start a career is to enroll in a formal educational program at a university or college. This helps students learn concepts, theories, methods, etc. they need for their profession. Moreover, a degree such as a bachelor's degree is required by employers. In this context, the first step for Connor is to earn a bachelor's degree in Civil Engineering.

Besides this, an internship is recommended after earning a degree because this is the way students can gain real-life work experience, which is considered positive by employers. This means the next step should be an internship.

Finally, Connor can seek a job to design bridges and other buildings because after the degree and internship he will have the experience and knowledge required by employers and by the job.

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Type the correct answer in the box. Spell all words correctly.

AVprozaik [17]

Answer:

Mechanical engineer? Thats my guess I didnt have alot of options sorry if I am wrong

Explanation:

3 0

3 years ago

Which of the following is NOT a breach of Netiquette?

alexandr402 [8]

Answer:

I need some more point and i do not understand your question

Explanation:

7 0

2 years ago

A resistance of 30 ohms is placed in a circuit with a 90 volt battery. What current flows in the circuit?

blagie [28]

Answer:

Explanation:

Using Ohms law U=I×R solve for I by I=U/R

4 0

2 years ago

An oxygen–nitrogen mixture consists of 35 kg of oxygen and 40 kg of nitrogen. This mixture is cooled to 84 K at 0.1 MPa pressure

Tamiku [17]

Answer:

The mass of oxygen in liquid phase = 14.703 kg

The mass of oxygen in the vapor phase = 20.302 kg

Explanation:

Given that:

The mass of the oxygen $m_{O_2}$ = 35 kg

The mass of the nitrogen $m_{N_2}$ = 40 kg

The cooling temperature of the mixture T = 84 K

The cooling pressure of the mixture P = 0.1 MPa

From the equilibrium diagram for te-phase mixture od oxygen-nitrogen as 0.1 MPa graph. The properties of liquid and vapor percentages are obtained.

i.e.

Liquid percentage of $O_2$ = 70% = 0.70

Vapor percentage of $O_2$ = 34% = 0.34

The molar mass (mm) of oxygen and nitrogen are 32 g/mol and 28 g/mol respectively

Thus, the number of moles of each component is:

number of moles of oxygen = 35/32

number of moles of oxygen = 1.0938 kmol

number of moles of nitrogen = 40/28

number of moles of nitrogen = 1.4286 kmol

Hence, the total no. of moles in the mixture is:

$N_{total} = 1.0938+1.4286$

$N_{total} = 2.5224 \ kmol$

So, the total no of moles in the whole system is:

$N_f + N_g = 2.5224 --- (1)$

The total number of moles for oxygen in the system is

$0.7 \ N_f + 0.34 \ N_g = 1.0938 --- (2)$

From equation (1), let N_f = 2.5224 - N_g, then replace the value of N_f into equation (2)

∴

0.7(2.5224 - N_g) + 0.34 N_g = 1.0938

1.76568 - 0.7 N_g + 0.34 N_g = 1.0938

1.76568 - 0.36 N_g = 1.0938

1.76568 - 1.0938 = 0.36 N_g

0.67188 = 0.36 N_g

N_g = 0.67188/0.36

N_g = 1.866

From equation (1)

$N_f + N_g = 2.5224$

N_f + 1.866 = 2.5224

N_f = 2.5224 - 1.866

N_f = 0.6564

Thus, the mass of oxygen in the liquid and vapor phases is:

$m_{fO_2} = 0.7 \times 0.6564 \times 32$

$m_{fO_2} = 14.703 \ kg$

The mass of oxygen in liquid phase = 14.703 kg

$m_{g_O_2} = 0.34 \times 1.866 \times 32$

$m_{g_O_2} = 20.302 \ kg$

The mass of oxygen in the vapor phase = 20.302 kg

8 0

2 years ago

Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an

Lera25 [3.4K]

Answer:

$\dot Q_{out} = 13369.104\,kW$

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

$-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0$

The rate of heat transfer between the turbine and its surroundings is:

$\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}$

The specific enthalpies at inlet and outlet are, respectively:

$h_{in} = 3076.41\,\frac{kJ}{kg}$

$h_{out} = 2675.0\,\frac{kJ}{kg}$

The required output is:

$\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW$ $\dot Q_{out} = 13369.104\,kW$

4 0

3 years ago