Answer:
See Explaination
Explanation:
1)here for given stress strain curve graph is given as follows
where for getting stress,S=F/A=4F/(pi*(50*10^-3)^2)
for strain=e=dl/l=dl*10^-3/100 mm/mm or m/m
2)so graph is as follows
3)for getting youngs modulus of elasticity we must know slope of graph stress verses strain and for straight line in elastic region upto 12 point we have elastic region and from that we get E as
E=slope of graph for first 12 points=S/e=14.5665*10^9/.812=17.9390*10^9 N/m2
4)for getting ultimate tensile stress at which specimen bears maximum load without failure so we get UTS as
UTS=maximum load/area=40*10^6/1.9634=20.3728*10^6 N/m2
5)percentage reduction in area is given by
percentage reduction in area=[original area-final area/original area]*100
Percent reduction=[5062-10^2]*100/50^2=96%
6)percentage elongation is given by
percent elongation=[final length-original length/original length]*100
final length at fractureis=14.56+100=114.56 mm
so we get percent elongation as=[114.56-100/100]*100=14.56%
7)true fracture stress is given by load at fracture devided by true area at fracture
Sf=load/(true area)=4*28*10^3/(pi*(10*10^-3)^2)=356.5070*10^6 N/m2
