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marishachu [46]

3 years ago

11

According to the place-time model of interaction, when people are in the same place, but at different times, this is an example

of what type of communication?

1 answer:

STALIN [3.7K]3 years ago

3 0

Answer: Shift work communication.

Explanation:

Shift work communication is a type of communication that exist between shift workers, or people at different time zones.

Shift work consists of a three eight hours shift within 24 hours.

Keeping up with a shift work communication requires planning, time management and commitment. It also requires using various communication channels.

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The efficiency of a steam power plant can beincreased by bleeding off some of the steam thatwould normally enter the turbine and

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In some states, repair shops can accept used oil from do-it-yourselfers or ____________.

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Answer:

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3 years ago

A 1m3 tank containing air at 25℃ and 500kPa is connected through a valve to

Aliun [14]

Answer:

The right answer is "2.2099 m³".

Explanation:

Given:

Mass,

m = 5 kg

Temperature,

T = 35℃

or,

= 35 + 273

Pressure,

P = 200 kPa

Gas constant,

R = 0.2870 kj/kgK

By using the ideal gas equation,

The volume will be:

⇒ $PV=mRT$

or,

⇒ $V=\frac{mRT}{P}$

By substituting the values, we get

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8 0

3 years ago

The conditions at the beginning of compression in an Otto engine operating on hot-air standard with k=1.35 and 101.325 kPa, 0.05

Katyanochek1 [597]

Answer:

$P_m=181.42 KPa$

Explanation:

$P_1=101.325 KPa,V_1=0.05m^3,T_1=32C$ ,K=1.35

Clearance is 8%.

Heat added=15 KJ

We know that compression ratio $r=1+\dfrac{1}{C}$

$r=1+\dfrac{1}{0.08}$

r=13.5

$r=\dfrac{V_1}{V_2}$

$13.5=\dfrac{0.05}{V_2}$

$V_2=3.7\times 10^{-3}$

We know that efficiency of otto cycle

$\eta =1-\dfrac{1}{r^{k-1}}$

$\eta =1-\dfrac{1}{13.5^{1.35-1}}$

$\eta =0.56$

$\eta =\dfrac{W}{Q}$

W is the work out put and Q is the heat addition.

$0.56 =\dfrac{W}{15}$

W=8.4 KJ

We know that Work =Mean effective pressure x swept volume.

Here swept volume $V_s=V_1-V_2$

$V_s=0.05-3.7\times 10^{-3}$

$V_s=0.0463 m^3$

Noe by putting the values

Work =Mean effective pressure x swept volume.

$8.4=P_m\times 0.0463$

$P_m=181.42 KPa$

6 0

3 years ago