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andrey2020 [161]
3 years ago
6

(x-1)^7/2 - (x-1)^3/2 factor and simplify. Show step-by-step solution.

Mathematics
2 answers:
Neko [114]3 years ago
4 0
(x-1)^{7/2} -(x-1) ^{3/2}= \\ =(x-1)^{3/2}*(x-1) ^{4/2}-(x-1) x^{3/2}= \\ =(x-1) ^{3/2}*((x-1) ^{2} - 1) = \\ =(x-1) ^{3/2}*(x-1+1)*(x-1-1) = \\ =x*(x-2)*(x-1) ^{3/2}
telo118 [61]3 years ago
4 0

(x-1)^3/2((x-1)^2-1) =(x+1)(x-1)^5/2


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A is the correct option.

Explanation:

We have been given that (2r - 3s)^{12}

The r^{th} term of a binomial expansion (a+b)^n is given by

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For the given binomial expansion, we have

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On plugging this value in the above formula, we have

t_2=^{12}C_{2-1}(2r)^{12-2+1}(-3s)^{2-1}\\\\t_2=^{12}C_1 (2r)^{11}(-3s)^{1}\\\\t_2=\frac{12!}{1!11!}(2)^{11}r^{11}(-3)s\\\\t_2=12\cdot (2)^{11}(-3)r^{11}s\\\\t_2=-73728r^{11}s

Therefore, the second term is -73728r^11 s

A is the correct option.



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