Answer:
695.87 Hz
Step-by-step explanation:
Using the equation for Doppler shift, the frequency of the apparent sound is f' = f(v ± v')/(v ± v") where f = frequency of sound emitted by the plane's engine = 485 Hz, v = speed of sound in air = 330 m/s, v' = speed of crowd(detector) = 0 m/s (since the crowd are stationary) and v" = speed of plane(source) = 100 m/s
So, f' = f(v ± v')/(v ± v")
f' = f(v ± 0)/(v ± v")
f' = fv/(v ± v")
Since the source moves towards the detector, we use a minus a minus sign in the denominator to get a shift upwards in frequency since a shift upwards means the objects are moving closer to each other.
So,
f' = fv/(v - v")
Substituting the values of the variables into the equation, we have
f' = 485 Hz × 330 m/s/(330 m/s - 100 m/s)
f' = 160050 Hzm/s ÷ 230 m/s
f' = 695.87 Hz
Answer:
Step-by-step explanation:
Answer:
25 (price of 1 mug)
40 ( price of 1 tumbler)
Step-by-step explanation:
15 x 17 = 255
880 - 255 = 625
625 ÷ (17+8) = 25 (price of 1 mug)
25+15 = 40 ( price of 1 tumbler)
Answer:
56.35 km ≈ 56 km
Step-by-step explanation:
Conversion factor: 1 mi ≈ 1.61 km
Therefore:
56.35 km ≈ 56 km