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Viefleur [7K]
3 years ago
13

What are the orbital models for these notations?

Chemistry
2 answers:
-BARSIC- [3]3 years ago
7 0

Answer:

use photomath

Explanation:

photomath can give you each step

masha68 [24]3 years ago
3 0

Answer:

It's a hard concept but once you get it it's easy

Explanation:

1s, Stands for sublevel 1

2s, 2p sublevel 2

3s, 3p, 3d sublevel 3

s can hold 2 electrons

p can hold 6 electrons

d can hold 10 electrons

for orbital notation

S= 1 box (can hold 2 electrons per box)

P= 3 boxes

D= 5 boxes

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When 75.5 grams of phosphorus pentachloride react with an excess of water, as shown in the unbalanced chemical equation below, h
AnnyKZ [126]

Answer:

Explanation: M(PCL5)= 31 + 5(35.5)

=208.5g/mol

M(H20)= 18g/mol

n(PCL5) = 75.5÷208.5

= 0.362mol

n(HCl)/n(PCL5)= 5/1

n(HCl)= 5×0.362

=1.81mol of HCl

6 0
3 years ago
Name one element with similar chemical properties to lithium
marysya [2.9K]

Answer:

Sodium

Explanation:

Its neighbor to the bottom (sodium) has similar properties to lithium. Group trends are very strong for the Group 1 (alkali) and Group 2 (alkaline earths) metals. Group 1 elements behave very similarly to each other.

4 0
3 years ago
Help please,just the answers which student​
BARSIC [14]

Answer:

Students A, B, and E

Explanation:

Student A is playing in the lab, student B is sniffing the flask, you're supposed to waft, and student E is eating while working.

5 0
3 years ago
Read 2 more answers
What effect does rapid exhalation of CO2 during exercise have on the concentration of H2CO3 in the blood?
lubasha [3.4K]
<span>Humans breathe in oxygen and breathe out carbon dioxide.During the process of breathing, humans convert sugar into energy. Carbon dioxide is a waste product of this process. Carbon dioxide is released into the blood, travels to the lungs and is exhaled. Because carbon dioxide is a weak acid, the more carbon dioxide in the blood, the more acidic the blood becomes.</span>
4 0
3 years ago
For the reaction;
ankoles [38]

Answer:

At equilibrium:

[H2] = 0.005 M

[Br2] = 0.105 M

[HBr] = 0.189 M

Explanation:

H2(g) + Br2(g) ⇄ 2HBr

an "x" value will be used from reactant to produced "2x"

so at equilibrium:

[H2] = 0.1 - x

[Br2] = 0.2 - x

[HBr] = 2x

we know that Kc=[HBr]²/[H2][Br2]

Thus 62.5 = (2x)²/(0.1-x)(0.2-x)

this generate a quadratic equation: 58.5x² - 18.75x + 1.25 = 0

the x₁ = 0.23   x₂ = 0.09457

we pick 0.09457 because the two reactants can not make more than what they have. x₁ is higher than both initial reactant concentration

Then we substitute the "x₂" value at equilibrium:

[H2] = 0.1-0.09457 = 0.005 M

[Br2] = 0.2-0.09457 = 0.105 M

[HBr] = 2*0.09457 = 0.189 M

7 0
3 years ago
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