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2 years ago

If I started with 42.00 L of oxygen (O2) gas, how many grams is that?

Chemistry

1 answer:

belka [17]2 years ago

5 0

Answer:

42 liters of oxygen (liquid) weighs 47900 grams.

Explanation:

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2 years ago

What is the total number of atoms in the molecule

serg [7]

Answer:

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Explanation:

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2 years ago

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3 years ago

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

qaws [65]

The question is incomplete, here is the complete question:

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:

$CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$

In the second step, acetylene, carbon dioxide and water react to form acrylic acid:

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Write the net chemical equation for the production of acrylic acid from calcium carbide, water and carbon dioxide. Be sure your equation is balanced.

Answer: The net chemical equation is written below.

Explanation:

The intermediate balanced chemical reaction are:

(1) $CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$ ( × 6 )

(2) $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

To omit acetylene from the net chemical reaction, we multiply Equation (1) by 6.

Equation 1: $6CaC_2(s)+12H_2O(g)\rightarrow 6C_2H_2(g)+6Ca(OH)_2(s)$

Equation 2: $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Net chemical equation: $6CaC_2(s)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)+6Ca(OH)_2(s)$

Hence, the net chemical equation is written above.

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2 years ago

The circles in the diagrams below represent energy levels in an atom, and the arrows show electron (blue dot) transitions from o

Hoochie [10]

Ranking of the atom from highest to lowest is as follows:
Highest
Arrow = from outer edge to center
2nd Highest
Arrow = second closest ring to the outer edge to center
3rd Highest
Arrow = middle circle to center
Lowest
Arrow = outer edge to middle circle

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3 years ago