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KengaRu [80]
3 years ago
15

What happens to a confined gas at a constant temperature when the volume is reduced to 1/2

Chemistry
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

When it reduce then it going be real cold.

Explanation:

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In your own words, explain how multiple approaches to a scientific investigation can be used to obtain the same result. Provide
aleksandr82 [10.1K]

Answer:B

Explanation:

5 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
2 years ago
A dialysis unit requires 70000 mL of distilled water. How many gallons of water are needed? (1 gal = 4 qt)
Lady bird [3.3K]

Answer: 19.25 gallons

Explanation: 1 ml = 0.0011 quart

Given:  4 quarts = 1 gallon

Thus if 1 ml is equal to 0.0011 quart

70000 ml  is equal to =\frac{0.0011}{1}\times 70000=77quart

Now if 4 quarts is equal to 1 gallon.

77 quarts is is equal to=\frac{1}{4}\times 77=19.25gallons




5 0
3 years ago
Read 2 more answers
Of Be3+ , Li2+ , and He1+
Mama L [17]

Answer:He 1+

Explanation:

Both Hydrogen atom and helium ion are one electron species. Hence we expect the spectrum of the helium ion to closely resemble that of hydrogen atom also containing one valence electron.

5 0
3 years ago
At 850 K, the equilibrium constant for the reaction
Sphinxa [80]

Answer:

Answers are in the explanation.

Explanation:

<em>Given concentrations are:</em>

  • <em>SO₂ = 0.20M O₂ = 0.60M SO₃ = 0.60M</em>
  • <em>SO₂ = 0.14M O₂ = 0.10M SO₃ = 0.40M </em>
  • <em>And SO₂ = 0.90M O₂ = 0.50M SO₃ = 0.10M</em>

<em />

In the reaction:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kc is defined as:

Kc = 15 = [SO₃]² / [O₂] [SO₂]²

<em>Where concentrations of each species are equilbrium concentrations.</em>

<em />

Also, you can define Q (Reaction quotient) as:

Q = [SO₃]² / [O₂] [SO₂]²

<em>Where concentrations of each species are ACTUAL concentrations.</em>

<em />

If Q > Kc, the reaction will shift to the left until Q = Kc;

If Q < Kc, the reaction will shift to the right until Q = Kc

If Q = Kc, there is no net reaction because reaction would be en equilibrium.

Replacing with given concentrations:

  • Q = [0.60M]² / [0.60M] [0.20M]² = 15; Q = Kc → No net reaction
  • Q = [0.40M]² / [0.10M] [0.14M]² = 82; Q > Kc, → Reaction will shift to the left
  • Q = [0.10M]² / [0.50M] [0.90M]² = 0.015; Q < Kc → Reaction will shift to the right

<em />

8 0
3 years ago
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