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DENIUS [597]
4 years ago
9

The rare earth elements include A. the actinide series and the alkaline earth metals. B. the alkali metals and the transition me

tals. C. the lanthanide series and the actinide series. D. the lanthanide series and the alkali metals.
Chemistry
1 answer:
kolezko [41]4 years ago
8 0
The answer is A because Alkaline are gases in earth's atmosphere <span />
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a liquid that boils at a low temperature and evaporates rapidly at room temperature is describe as being
Sunny_sXe [5.5K]

Answer: Volatile

Explanation:

like ethanol(alcohol) it evaporates when you put it in the hand, really fast.

Some people think that it dries when it really evaporated at room temperature from liquid to gas

5 0
3 years ago
Balance this equation pls<br><br> __NaCl + __CaF2→ __NaF +__CaCl2
maw [93]

Answer:

2NaCl + 1CaF²--------》2NaF + 1CaCl²

3 0
4 years ago
Read 2 more answers
At a given temperature, 4.06 atm of H2 and 3.5 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure
Llana [10]

<u>Answer:</u> The value of K_p for the given chemical reaction is 0.1415

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_p is written as:

K_p=\frac{p_{C}^cp_{D}^d}{p_{A}^ap_{B}^b}

For the given chemical equation:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g)

The expression for K_p for the following equation is:

K_p=\frac{(p_{HCl})^2}{(p_{H_2)}(p_{Cl_2})}

We are given:

p_{HCl}=1.418atm\\p_{H_2}=4.06atm\\p_{Cl_2}=3.5atm

Putting values in above equation, we get:

K_p=\frac{(1.418)^2}{(4.06)\times (3.5)}\\\\K_p=0.1415

The value of K_p for the given chemical reaction is 0.1415

5 0
3 years ago
What is Radio Waves and its defonation
Gala2k [10]

Answer:

radio waves are the sound waves that are produces by a radio

Explanation:

6 0
3 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

brainly.com/question/14044066

#SPJ4

8 0
1 year ago
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