Answer:
The section of the bar is 2.92 inches.
Explanation:
Mass of the steel cut ,m = 1.00 kg = 1000 g
Volume of the steel bar = V = Area × height
Height of the of the section of bar = h
Area of Equilateral triangular = 
a = 2.50 inches
Cross sectional area of the steel mass = A


Density of the steel = d =




h = 2.92 inches
The section of the bar is 2.92 inches.
The answer is D. A positively charged sodium Ion and a negatively charged chlorine ion form an ionic bond.