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Alex73 [517]
3 years ago
6

Given the starting solution had a concentration of 1.25 m, how many moles of co[h2o]6cl2 were available in the amount of startin

g solution you used
Chemistry
1 answer:
siniylev [52]3 years ago
3 0
Molarity of solution is defined as number of moles present in one liter solution. Mathematically, it is expressed as 
Molarity = \frac{\text{number of moles}}{\text{volume of solution(l)}}

Thus, if 1 mole of solute is present in 1 liter solution, molarity of solution is 1 M.

In present case, initial conc, of solution was 1.25 M.

∴ Number of moles of <span>co[h2o]6cl2  available initially = 1.25 mole, if the solution is 1 liter</span>
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Part B Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrobromic
Doss [256]

Answer:

HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)

Explanation:

A neutralization reaction is a process in which an acid, aqeous HBr reacts completely with an appropriate amount of base, aqueous LiOH to produce salt, aqueous LiBr and water, liquid H2O only.

HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)

Acid + base → Salt + Water.

During this reaction, the hydrogen ion, H+, from the HBr is neutralized by the hydroxide ion, OH-, from the LiOH to form the water molecule, H2O.

Thus, it is called a neutralization reaction.

4 0
3 years ago
According to the activity series, which one of the following reactions will occur?
Korvikt [17]

Answer:

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Explanation:

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3 years ago
ASAP PLEASE<br> Explain the difference between heat and temperature.
Irina-Kira [14]

The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.

4 0
3 years ago
Read 2 more answers
According to Boyle's law, for a fixed quantity of gas at a given temperature, what quantity relating pressure P and volume V is
yan [13]

<u>Answer:</u> The quantity relating pressure and volume is PV=k and the size of the tank must be 1.92\times 10^3L

<u>Explanation:</u>

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

Mathematically,

P\propto \frac{1}{V}

Or,

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=160atm\\V_1=12L\\P_2=1atm\\V_2=?L

Putting values in above equation, we get:

160atm\times 12L=1atm\times V_2\\\\V_2=\frac{160\times 12}{1}=1920L=1.92\times 10^3L

Hence, the size of the tank must be 1.92\times 10^3L

7 0
3 years ago
A flash distillation chamber operating at 101.3 kpa is separating an ethanol water mixture the feed mixture contains z weight et
Alex73 [517]

Answer:

The answer is [\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454 mol/hr

[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454mol/hr

Explanation:

For flash distillation

F = V+L

\frac{V}{F} + \frac{L}{F} = 1

\frac{F}{V} -\frac{L}{V} = 1

Fz = Vy+Lx

Y = \frac{F}{V}\times Z - \frac{L}{V}\times X                  let, \frac{V}{F} = F

y = \frac{Z}{F} -[ \frac{1}{F} -1]\times X

Highlighted reading

F = 299;  \frac{V}{F} = 0.85 ; z = 0.36

y = \frac{0.36}{0.85} - (-0.15)\times X

 = 0.423 + 0.15x ------------(i)

y^{*} = -43.99713x^{6} + 148.27274x^{5} - 195.46x^{4}+127.99x^{3}-43.3x^{2}+ 7.469x^{}+ 0.02011

At equilibrium, y^{*} = y

0.423+0.15x^{} = y^{*}

-43.99713x^{6}+ 148.27274x^{5} - 195.46x^{4}+127.99x^{3}-43.3x^{2}+ 7.319x^{}-0.403

F(x) for Newton's Law

Let x_{0} = 0

     x_{1}     = \frac{0-[{-0.403}]}{7.319}

             = 0.055

     x_{2}      = \frac{{0.055}-{f(0.055)} {{{{{{{}}}}}}}}{f^{'} (0.055)}

             = \frac{{(0.055)}-(-0.11)}{3.59}

             = 0.085

    x^{3}    = \frac{{0.085}-(0.024)}{2.289}

           = 0.095

   x^{4}     = \frac{{0.095}-(-0.0353)}{-1.410}

            = 0.07

From This x and y are found from equation (i) and L and V are obtained from \frac{V}{F}  and F values

[\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454 mol/hr

[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454mol/hr

   

8 0
3 years ago
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