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Alex73 [517]
3 years ago
6

Given the starting solution had a concentration of 1.25 m, how many moles of co[h2o]6cl2 were available in the amount of startin

g solution you used
Chemistry
1 answer:
siniylev [52]3 years ago
3 0
Molarity of solution is defined as number of moles present in one liter solution. Mathematically, it is expressed as 
Molarity = \frac{\text{number of moles}}{\text{volume of solution(l)}}

Thus, if 1 mole of solute is present in 1 liter solution, molarity of solution is 1 M.

In present case, initial conc, of solution was 1.25 M.

∴ Number of moles of <span>co[h2o]6cl2  available initially = 1.25 mole, if the solution is 1 liter</span>
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False

Explanation:

Sound waves are longitudinal mechanical waves.

Mechanical waves are waves that requires a medium to propagate them.

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  • Sound wave is a longitudinal wave.
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7 0
3 years ago
How many moles of silicon are in 5.9 X 10 to the 24 power atoms of silicon​
Dimas [21]

Answer:

9.79740949850 moles

Explanation:

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Side Note: Please let me know if you need any clarifications about this!

8 0
2 years ago
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Significant Figures: How many significant figures<br> are in 865,010?
Harrizon [31]

Answer: There are five significant figures in 865,010.

Explanation:

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Rules for counting significant figures is as follows.

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  • Trailing zeros are counted in a non-zero figure. For example, 0.00250 has three significant figures.
  • Leading zeros are not counted. For example, 0.0025 has two significant figures.

So, in the given figure 865010 has five significant figures and the trailing zero will not be counted.

Thus, we can conclude that there are five significant figures in 865,010.

7 0
3 years ago
A ball has a mass of 140 g. What is the force needed to accelerate the ball at 25 m/s2? (Formula: F=ma) 3.5 N 115 N 165 N 4.5
Ksju [112]
<h3>Answer:</h3>

3.5 Newton

<h3>Explanation:</h3>

We are given;

Mass of the ball = 140 g

Acceleration = 25 m/s²

Required to find the force;

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To get the force we substitute the value of m and a in the formula;

Therefore;

F = 0.14 kg × 25 m/s²

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Hence, the force needed to accelerate the ball is 3.5 N

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34kurt
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