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Darina [25.2K]
3 years ago
5

What geologic action may produce a chain of volcanic islands

Chemistry
2 answers:
Vaselesa [24]3 years ago
6 0

Answer:

a hot spot

Explanation:

Volcanic island chains are formed independently of the movements of tectonic plates. They are found above the hot spots caused by the mantle. Currents of hot materials from the mantle pierce a path through the crust, creating a chain of hot spot volcanoes. They form volcanoes that produce highly fluid lava that build the flat volcanoes of the shield. Example: Mauna loa, Hawaii.

Zinaida [17]3 years ago
5 0

The chains of volcanic islands can be found mostly alongside the borders of the convergent plate boundaries, more specifically, on the convergent boundaries between an oceanic and continental tectonic plates. That can easily be seen by the so called ''Ring of Fire'' where there's numerous chains of volcanic islands

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Enough of a monoprotic acid is dissolved in water to produce a 1.64 M solution. The pH of the resulting solution is 2.82 . Calcu
Lady bird [3.3K]

Answer:

Ka = 1.39x10⁻⁶

Explanation:

A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

<em>Where Ka is:</em>

Ka = [H⁺] [X⁻] / [HX]

<em>Where [] is the molar concentration in equilibrium of each specie. </em>

The equilibrium is reached when some HX reacts producing H+ and X-, that is:

[HX] = 1.64M - X

[H⁺] = X

[X⁻] = X

As pH is 2.82 = -log [H⁺]:

[H⁺] = 1.51x10⁻³M:

[HX] = 1.64M - 1.51x10⁻³M = 1.638M

[H⁺] = 1.51x10⁻³M

[X⁻] = 1.51x10⁻³M

And Ka is:

Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]

<h3>Ka = 1.39x10⁻⁶</h3>
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Rank the following carboxylic acids from strongest (1) to weakest (4)
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Answer:

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Explanation:

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More electronegative atom of halogen is , stronger acid will be.

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Answer: Option (d) is the correct answer.

Explanation:

Steps involved for the given reaction will be as follows.

Step 1: 2NO \Leftrightarrow N_{2}O_{2}    (fast)

Rate expression for step 1 is as follows.

               Rate = k [NO]^{2}

Step 2: N_{2}O_{2} + H_{2} \rightarrow N_{2}O + H_{2}O

This step 2 is a slow step. Hence, it is a rate determining step.

Step 3. N_{2}O + H_{2} \rightarrow N_{2} + H_{2}O    (fast)

Here, N_{2}O_{2} is intermediate in nature.

All the steps are bimolecular and it is a second order reaction. Also, there is no catalyst present in this reaction.

Thus, we can conclude that the statement step 1 is the rate determining step, concerning this mechanism is not directly supported by the information provided.

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