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RideAnS [48]
3 years ago
13

What is the difference between a dipole-dipole interaction and an ion-dipole interaction?

Chemistry
1 answer:
Andru [333]3 years ago
3 0
A dipole-dipole interaction is a force of attraction between slightly positive hydrogen on one molecule and a slightly negative atomon another molecule while ion-dipole interaction is force between an ion and a polar molecule
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Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 42. g of butane is m
taurus [48]

Answer:

127 grams of carbon dioxide

Explanation:

We need to determine the chemical equation first. Butane has a chemical formula of C_4H_{10}, oxygen is O_2, carbon dioxide is CO_2, and water is H_2O. The reactants are butane and oxygen and the products are carbon dioxide and water. So we write:

C_4H_{10}+O_2 ⇒ CO_2+H_2O

But remember! We need to balance this. Currently, there are 4 carbon atoms (C), 10 hydrogen atoms (H), and 2 oxygen atoms (O) on the left, while there are 1 carbon atom (C), 2 hydrogen atoms (H), and 3 oxygen atoms (O) on the right. Let's place a coefficient of 4 in front of the carbon dioxide and a coefficient of 5 on the water, so that we have equal numbers of carbon and hydrogen atoms on each side:

C_4H_{10}+O_2 ⇒ 4CO_2+5H_2O

However, we need to ensure that there are equal numbers of O atoms, as well. On the left, we have 2 and on the right we have 13, so let's put a coefficient of 6.5 on the oxygen:

C_4H_{10}+6.5O_2 ⇒ 4CO_2+5H_2O

Finally, multiply everything by 2 to get whole number coefficients:

2C_4H_{10}+13O_2 ⇒ 8CO_2+10H_2O

Ah, now we can actually get to the problem!

We need to determine the limiting reactant, so let's convert the 42 g of butane and 150 g of oxygen into moles of any product, say, carbon dioxide. To convert to moles, we need to find the molar mass of each compound.

The molar mass of butane is 4 * 12.01 + 10 * 1.01 = 58.14 g/mol, while the molar mass of oxygen is 2 * 16 = 32 g/mol. We can now set up the equations:

42 gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}} *\frac{8molCO_2}{2molC_4H_{10}} =2.8896molCO_2

150 gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{13molO_2} =2.8846molCO_2

Clearly, we see that 2.8846 < 2.8896, which means that oxygen is the limiting reactant. In other words, the most products can be made when the oxygen is all used up.

Now let's finally convert moles of carbon dioxide into grams by multiplying by its molar mass, which is 12.01 + 2 * 16 = 44.01 g/mol:

2.8846molCO_2*\frac{44.01gCO_2}{1molCO_2} =127gCO_2

Notice that we have 3 significant figures because we had 3 significant figures at the start with 150. grams of oxygen.

<em>~ an aesthetics lover</em>

4 0
3 years ago
An atom that has lost or gained electrons is known as an ion.
rjkz [21]
It is true because it just is
3 0
2 years ago
Which of the following is a sign that a valley glacier has moved through an area? *
Dmitry_Shevchenko [17]
B. The rocks carried by the glacier would leave the marks
7 0
3 years ago
A student wants to reclaim the iron from an 18.0-gram sample of iron(III) oxide, which
lilavasa [31]

Answer:

m_{Fe}=12.6gFe

Explanation:

Hello,

In this case, since we have grams of iron (III) oxide whose molar mass is 159.69 g/mol are able to compute the produced grams of iron by using its atomic mass that is 55.845 g/mol and their 2:4 molar ratio in the chemical reaction:

m_{Fe}=18.0gFe_2O_3*\frac{1molFe_2O_3}{159.69gFe_2O_3}*\frac{4molFe_2O_3}{2molFe_2O_3} *\frac{55.845gFe}{1molFe_2O_3} \\\\m_{Fe}=12.6gFe

Best regards.

3 0
3 years ago
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A preliminary untested explanation that tries to explain how or why things happen in the manner observed is a scientific
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It is a scientific hypothesis. A scientific hypothesis must be testable, however there is a significantly more grounded necessity that a testable speculation must meet before it can truly be viewed as logical. This foundation comes essentially from crafted by the rationalist of science Karl Popper, and is called "falsifiability".
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3 years ago
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