The correct answer is
<span>C) -10.7 m/s
In fact, the first rock is moving upward with velocity +4.5 m/s, while the second rock is moving downward with velocity -6.2 m/s, with respect to a fixed reference frame. In the reference frame of the first rock, instead, the second rock is moving with velocity equal to its velocity in the fixed frame minus the velocity of the reference frame of the first rock:
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Sunspot cycles, solar flares, prominences, layers of the Sun, coronal mass<span> ejections, and </span>nuclear<span> reactions</span>
Answer:
14J
20000J
200J
Explanation:
formula :W=FS
W:work done
F:force (N)
S:displacement moved in direction of force (m)
1) 20N×0.7m
=14J
2) 400N×50m
= 20000J
3) 10N×20m
=200J
To solve this problem, apply the concepts given from Ohm's Law. From there we will obtain the derivative of the function with respect to time and with the previously given values we will proceed to find the change in current as a function of the derivative

Here
I = Current
V = Voltage
R = Resistance
Taking the derivative we will have,

Our values are given as,




Replacing we will have that


Rearranging to find the current through the time,


Therefore the change of the current is -0.000026A per second