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kap26 [50]
1 year ago
8

A boater is accompanied by a person at least 16 years of age. In michigan, what is the youngest age that this person can be and

legally operate a boat powered by a motor of more than 35 hp?.
Physics
1 answer:
dexar [7]1 year ago
5 0

The youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.

<h3 /><h3>What is electric power?</h3>

It is the rate of the electric work done. Its unit is the watt. Horsepower is the unit of power.

A person under the age of 12 may only legally operate a boat with a motor that has more than 6 horsepower but no more than 35 horsepower

if they meet two requirements: they have a boating safety certificate, which they must have on board; and they are being closely watched by an adult who is at least 16 years old.

Hence the youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.

To learn more about electric power refer to the link;

brainly.com/question/12316834?referrer=searchResults

#SPJ1

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Explanation:

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1 year ago
A baseball, which has a mass of 0.685 kg., is moving with a velocity of 38.0 m/s when it contacts the baseball bat duringwhich t
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Answers:

a) 65.075 kgm/s

b) 10.526 s

c) 61.82 N

Explanation:

<h3>a) Impulse delivered to the ball</h3>

According to the Impulse-Momentum theorem we have the following:

I=\Delta p=p_{2}-p_{1} (1)

Where:

I is the impulse

\Delta p is the change in momentum

p_{2}=mV_{2} is the final momentum of the ball with mass m=0.685 kg and final velocity (to the right) V_{2}=57 m/s

p_{1}=mV_{1} is the initial momentum of the ball with initial velocity (to the left) V_{1}=-38 m/s

So:

I=\Delta p=mV_{2}-mV_{1} (2)

I=\Delta p=m(V_{2}-V_{1}) (3)

I=\Delta p=0.685 kg (57 m/s-(-38 m/s)) (4)

I=\Delta p=65.075 kg m/s (5)

<h3>b) Time </h3>

This time can be calculated by the following equations, taking into account the ball undergoes a maximum compression of approximately 1.0 cm=0.01 m:

V_{2}=V_{1}+at (6)

V_{2}^{2}=V_{1}^{2}+2ad (7)

Where:

a is the acceleration

d=0.01 m is the length the ball was compressed

t is the time

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a=\frac{V_{2}^{2}-V_{1}^{2}}{2d} (8)

a=\frac{(57 m/s)^{2}-(-38 m/s)^{2}}{2(0.01 m)} (9)

a=90.25 m/s^{2} (10)

Substituting (10) in (6):

57 m/s=-38 m/s+(90.25 m/s^{2})t (11)

Finding t:

t=1.052 s (12)

<h3>c) Force applied to the ball by the bat </h3>

According to Newton's second law of motion, the force F is proportional to the variation of momentum  \Delta p in time  \Delta t:

F=\frac{\Delta p}{\Delta t} (13)

F=\frac{65.075 kgm/s}{1.052 s} (14)

Finally:

F=61.82 N

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