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lidiya [134]
2 years ago
15

A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces

, the box travels a total of 15.0 meters in 5.25 seconds.
Calculate the power developed by the unbalanced forces to move the box.



A
44.1 watts
B
143 watts
C
263 watts
D
750 watts
Physics
1 answer:
Flura [38]2 years ago
7 0

Answer: (b)

Explanation:

Given

Mass of box m=17\ kg

Applied force F=175\ N

Friction force f=-125\ N

Box travels a distance of s=15\ m

time taken t=5.25\ s

Net unbalanced force F_{net}=175-125=50\ N

Work done by the unbalanced force

\Rightarrow W=F_{un}\cdot s\\\Rightarrow W=50\times 15\\\Rightarrow W=750\ N

Power developed by unbalanced force

\Rightarrow P=\dfrac{W}{t}\\\\\Rightarrow P=\dfrac{750}{5.25}\\\\\Rightarrow P=142.85\approx 1423\ W

Thus, option (b) is correct.

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for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as-E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero  between the two charges,but we can find the points situated on the axial  line but  outside of charges where the electric field is zero.

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here we can not find a point between two charges and on the line joining  two charges  where the potential is zero.

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5 0
3 years ago
You are sitting on a deck of your house surrounded by oak trees. You hear the sound of an acorn hitting the deck. You wonder if
Black_prince [1.1K]

Answer: 96N

Explanation:

To calculate the velocity of the impact On the persons head, we have

h = gt²/2

14 = 9.81t²/2

t² = 28/9.8

t² = 2.86

t = 1.69s

V = u + at

V = 0 + 9.81*1.69

V = 16.58m/s

a(average) = (v1² + v2²) /2Δy

a(average) = 16.58² + 0)/2 * 0.005

a(average) = 274.8964/0.01

a(average) = 27489.64m/s²

Using newton's second law of motion,

F(average) = m * a(average)

F(average) = 0.0035 * 27489.64

F(average) = 96.21N

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8 0
2 years ago
Consider a particle with unit charge q, and mass m, in a constant magnetic field B directed along the positive z–axis. The parti
max2010maxim [7]

Answer:

it must be helical motion in which the charge particle will move uniformly along z axis and simultaneously it will move in circular path in xy plane.

Explanation:

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so we will have

F = q(\vec v \times \vec B)

so here we can say

F = q(u\hat i + w\hat k) \times (B \hat k)

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so here the net force on the charge is perpendicular to its x directional velocity along - Y direction

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4 0
2 years ago
What is relation of acceleration of a body to its mass and applied force​
irinina [24]
The law states that external forces cause objects to accelerate, and the amount of acceleration is directly proportional to the net force and inversely proportional to the mass of the object.


If you can’t copy and paste it just reword it
3 0
3 years ago
When energy is added to an object, it will vibrate at it's...
sergiy2304 [10]

Answer:

I think D

Explanation:

if energy is added,it wont stay the same,I beleive D is the only one that makes since,sorry if wrong

6 0
2 years ago
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