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lidiya [134]
3 years ago
15

A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces

, the box travels a total of 15.0 meters in 5.25 seconds.
Calculate the power developed by the unbalanced forces to move the box.



A
44.1 watts
B
143 watts
C
263 watts
D
750 watts
Physics
1 answer:
Flura [38]3 years ago
7 0

Answer: (b)

Explanation:

Given

Mass of box m=17\ kg

Applied force F=175\ N

Friction force f=-125\ N

Box travels a distance of s=15\ m

time taken t=5.25\ s

Net unbalanced force F_{net}=175-125=50\ N

Work done by the unbalanced force

\Rightarrow W=F_{un}\cdot s\\\Rightarrow W=50\times 15\\\Rightarrow W=750\ N

Power developed by unbalanced force

\Rightarrow P=\dfrac{W}{t}\\\\\Rightarrow P=\dfrac{750}{5.25}\\\\\Rightarrow P=142.85\approx 1423\ W

Thus, option (b) is correct.

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Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 7.1 W. While
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Answer:

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Answer:

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