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Citrus2011 [14]
2 years ago
5

Please help I’ll make u brainliest please

Physics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

14J

20000J

200J

Explanation:

formula :W=FS

W:work done

F:force (N)

S:displacement moved in direction of force (m)

1) 20N×0.7m

=14J

2) 400N×50m

= 20000J

3) 10N×20m

=200J

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Alexxandr [17]

Answer:

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3 0
3 years ago
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PLEASE HELP WILL GIVE BRAINLEST!!!
Aleks04 [339]

Answer:

huh what do u want tho its nothing bad

Explanation:

3 0
3 years ago
Which form of energy is involved in weighing fruit on a spring scale?
ser-zykov [4K]
There are two types of energies that are taking place in the fruit is weighed in a spring scale. These are the gravitational potential energy and the elastic potential energy. The gravitational potential energy could be primarily attributed to the elevation of the fruit with respect to the ground.
3 0
4 years ago
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A 10 kg runaway grocery cart runs into a spring with spring constant 250 n/m and compresses it by 60 cm. what was the speed of t
andrew-mc [135]
The initial kinetic energy of the cart is
K= \frac{1}{2} mv^2 (1)
where m is the mass of the cart and v its initial velocity.

Then, the cart hits the spring compressing it. The maximum compression occurs when the cart stops, and at that point the kinetic energy of the cart is zero, so all its initial kinetic energy has been converted into elastic potential energy of the spring:
U= \frac{1}{2}kx^2
where k is the spring constant and x is the spring compression.

For energy conservation, K=U. We can calculate U first: the compression of the spring is x=60 cm=0.60 m, while the spring constant is k=250 N/m, so
U= \frac{1}{2}kx^2= \frac{1}{2}(250 N/m)(0.60 m)^2=45 J

So, the initial kinetic energy of the cart is also 45 J, and from (1) we can find the value of the initial velocity:
v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 45 J}{10 kg} }  =3 m/s
7 0
3 years ago
A 20-car train standing on the siding is started in motion by the train’s engine. 2 cm slack is between each of the cars, which
My name is Ann [436]

Answer:

1.81 s

Explanation:

From the given information:

The links between the cars are:

1-2, 2-3, 3-4, 4-5, 5-6, 6-7, 7-8, 8-9, 9-10, 10-11, 11-12, 12-13, 13-14, 14-15, 15-16, 16-17, 17-18, 18-19, 19-20.

where;

1 denotes the first car that joins strongly attached to the engine.

There are 19 links from the above connections and each one of them has a 2 cm slack.

Thus; the total slack = 2 × 19 = 38 cm

However, the speed of the train = 21 cm/s

Then, the time taken by the pulse to travel the length of the train is expressed by using the formula:

= length / speed

= 38 / 21

= 1.81 seconds

Thus, the required time = 1.81 s

6 0
3 years ago
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