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Anna11 [10]
3 years ago
14

PLEASE JELP

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0
PLEASE JELP
What are the coordinates of the centroid of a triangle with vertices A(−6, 0) , B(−4, 4) , and C(0, 2) ? Enter your answers in the boxes.

For -3 1/3 you can use -10/3

pantera1 [17]3 years ago
8 0

Answer:  The required co-ordinates of the centroid are \left(-\dfrac{10}{3},2\right).

Step-by-step explanation:  We are to find the coordinates of the centroid of a triangle with vertices A(−6, 0) , B(−4, 4) , and C(0, 2).

We know that

the co-ordinates of the centroid of a triangle with vertices (a, b), (c, d) and (e, f) are given by

\left(\dfrac{a+c+e}{3},\dfrac{b+d+f}{3}\right).

Therefore, the co-ordinates of the centroid of triangle ABC are

\left(\dfrac{-6+(-4)+0}{3},\dfrac{0+4+2}{3}\right)\\\\\\=\left(\dfrac{-10}{3},\dfrac{6}{3}\right)\\\\=\left(-\dfrac{10}{3},2\right).

Thus, the required co-ordinates of the centroid are \left(-\dfrac{10}{3},2\right).

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kkurt [141]

Answer:

100 1/4

Step-by-step explanation:

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3 years ago
(pleas help) Which statement describes the following expression? 6 x (3,117 + 724)
miskamm [114]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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2a-6=4a<br><br> Solve for a<br><br> Check your work
algol [13]

Answer:

-3

Step-by-step explanation:

2a - 6 = 4a

subtract 2a giving you -6 = 2a

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5 0
3 years ago
Greatest to least: 17/20, 19/20, 0.19, 0.24
Yakvenalex [24]
19/20,17/20,0.24,0.19
5 0
3 years ago
What is the sum of the polynomials? (9x4−13x3−x−7)+(7x3−2x+1) A.) −6x^6+9x^4−3x^2−6 B.)−6x^6+9x^4−x−8 C.)9x^4−6x^3−x−8 D.)9x^4−6
irinina [24]
(9x^4-13x^3-x-7)+(7x^3-2x+1)=
9x^4-13x^3-x-7+7x^3-2x+1=
9x^4+(-13+7)x^3+(-1-2)x-7+1=
9x^4+(-6)x^3+(-3)x-6=
9x^4-6x^3-3x-6

Answer: Option <span>D.)9x^4−6x^3−3x−6</span>
5 0
3 years ago
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