The equation is -2x-4. u can use y2-y1/x2-x1.
The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:

Expand the function

Reorder the terms

Factor the expression

Factor out x -1

Expand

Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2

The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
Read more about functions at:
brainly.com/question/7784687
#SPJ1
Is it divide after the equal sign? I will text you on message. follow me
To find the answer, you must find the midpoint of their x-coordinates and their y-coordinates. To do that, you take the average between their x and y-coordinates.
So, in this case, it is:
x: (12+12)/2 = 24/2 = 12
y: (7-3)/2 = 4/2 = 2
So, the answer is: (12,2)
=7,892 , you could write out your numbers, then line them up to then add them.