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arlik [135]
2 years ago
11

A lender estimates that the closing costs on a $170,000 home loan will be $6,375.00. The actual closing costs were 4.0%of the lo

an amount. Determine if the closing costs were higher or
lower than the estimate and by what percent
higher by 0.25%
higher by 0.5%
lower by 0.25%
lower by 0.5%
Mathematics
1 answer:
Feliz [49]2 years ago
3 0

Answer:

  (a) higher by 0.25%

Step-by-step explanation:

The error in the estimate is found by comparing the estimated rate to the actual rate.

__

The rate of estimated closing costs is ...

  (estimated cost)/(home cost) × 100% = 6375/170000×100% = 3.75%

The actual rate is 4.00%.

  actual - estimate = 4.00% -3.75% = 0.25%

The actual closing costs were higher than the estimate by 0.25%.

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Answer:2034.7

Step-by-step explanation:

The equation is pi •r^2•h

R=6

H=18

3 0
3 years ago
Geometry help please show work due soon !
Thepotemich [5.8K]
R is 4 if I'm wrong sorry
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Television sizes are usually described by the length of their diagonal measure. What would be the listed size of the Tv whose wi
wel

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Step-by-step explanation:

7 0
2 years ago
I really need help. Someone please help me with this.
9966 [12]

Answer:

  angles 1, 3, 6, 8 = 142°

  angles 2, 4, 5, 7 = 38°

Step-by-step explanation:

Vertical angles and corresponding angles are congruent, as are alternate interior angles. Hence the angles 1, 3, 6, 8 are all congruent:

  ∠1 = ∠3 = ∠6 = ∠8 = 142°

Each of the remaining angles forms a linear pair with one or another of those, so is its supplement:

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7 0
3 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ss7ja [257]

Answer:

The probability that the plane is oveloaded is P=0.9983.

The pilot should take out the baggage and send it in another plain or have less passengers in the plain to not overload.

Step-by-step explanation:

The aircraft will be overloaded if the mean weight of the passengers is greater than 163 lb.

If the plane is full, we have 41 men in the plane. This is our sample size.

The weights of men are normally distributed with a mean of 180.5 lb and a standard deviation of 38.2.

So the mean of the sample is 180.5 lb (equal to the population mean).

The standard deviation is:

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Then, we can calculate the z value for x=163 lb.

z=\frac{x-\mu}{\sigma}=\frac{163-180.5}{5.97}=\frac{-17.5}{5.97}=   -2.93

The probability that the mean weight of the men in the airplane is below 163 lb is P=0.0017

P(\bar X

Then the probability that the plane is oveloaded is P=0.9983:

P(overloaded)=1-P(X

The pilot should take out the baggage or have less passengers in the plain to not overload.

7 0
3 years ago
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