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arlik [135]
2 years ago
11

A lender estimates that the closing costs on a $170,000 home loan will be $6,375.00. The actual closing costs were 4.0%of the lo

an amount. Determine if the closing costs were higher or
lower than the estimate and by what percent
higher by 0.25%
higher by 0.5%
lower by 0.25%
lower by 0.5%
Mathematics
1 answer:
Feliz [49]2 years ago
3 0

Answer:

  (a) higher by 0.25%

Step-by-step explanation:

The error in the estimate is found by comparing the estimated rate to the actual rate.

__

The rate of estimated closing costs is ...

  (estimated cost)/(home cost) × 100% = 6375/170000×100% = 3.75%

The actual rate is 4.00%.

  actual - estimate = 4.00% -3.75% = 0.25%

The actual closing costs were higher than the estimate by 0.25%.

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Step-by-step explanation:

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there is a direct path from gayle's house to the store. due to construction, the direct route is closed and gayle must travel 6
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Answer:

c2=10

Step-by-step explanation:

8^2+6^2=c2

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3 years ago
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Find the interquartile range (IQR) of the data in the dot plot below. chocolate chips 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10
Brums [2.3K]

*The dot plot is shown in the attachment below

Answer:

2

Step-by-step explanation:

Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).

First, let's write out each value given in the data. Each dot represents a data point.

We have:

2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7

=>Find the median:

Our median is the middle value. The middle value is the 6th value = 4

==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.

2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7

Our upper median = 5

==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.

2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7

Lower median = 3

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3 0
4 years ago
Two sides of a triangle have lengths of 7 ft and 15 fr. Which inequality represents the possible length for the third side, x?
Inessa05 [86]

6 < c < 20,

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3 0
3 years ago
Solve for x and y...............​
sladkih [1.3K]

Answer:

9. x=30, y=10\sqrt{3}

11. x=5\sqrt{3}, y=10\sqrt{3}

Step-by-step explanation:

9)

\sin x=\dfrac{10}{20}\\x=\sin^{-1}\left( \dfrac{1}{2} \right)=30^{\circ}\\y=\sqrt{20^2-10^2}=\sqrt{400-100}=\sqrt{300}=10\sqrt{3}

11)

\tan 60= \dfrac{15}{x}\\x=\dfrac{15}{\tan 60}=5\sqrt{3}\\y=\sqrt{(5\sqrt{3})^2+15^2}=\sqrt{75+225}=\sqrt{300}=10\sqrt{3}

Hope this helps!

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3 years ago
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