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siniylev [52]
3 years ago
12

Uranium-238 has a half-life of 4.5 billion years. Given that scientists estimate Earth's age to be 4.6 billion years, what is th

e most likely percentage of parent to daughter isotopes of this element currently existing on Earth? A. 10 percent B. 25 percent C. 50 percent D. 75 percent
Chemistry
2 answers:
larisa [96]3 years ago
5 0
B) 25 percent
hope this helps
hugs ~L
lorasvet [3.4K]3 years ago
5 0

Answer:

The correct answer is option C.

Explanation:

Half life of the uranium-238=t_{\frac{1}{2}}=4.5 \text{billion years}

Decay constant =\lambda

\lambda =\frac{0.693}{t_{\frac{1}{2}}}

\lambda =\frac{0.693}{4.5 \text{billion years}}=0.154 ({\text{billion year})^{-1}

Let the initial amount of U-238 be x

And the present amount of U-238 be x'.

A=A_o\times e^{-\lambda t}

A_o = Initial amount

A = Amount left after time t

x'=x\times e^{-0.154 ({\text{billion year})^{-1}\times 4.5\text{billion years}}

x'=x\times 0.500

Percentage of left amount:

\%=\frac{A}{A_o}\times 100

\%=\frac{x\times 0.5000}{x}\times 100=50.00\%

Hence,the correct answer is option C.

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Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
fig. 15 shows a simplified diagram of the electrolysis of a molten electrolyte containing lithium chloride. b. Describe how the
melisa1 [442]

During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.

<h3>What is electrolysis?</h3>

Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them.  In this process, the atoms and ions are interchanged by the addition or removal of electrons.

The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.

During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.

At anode :  2 Cl⁻ →    Cl₂ + 2e⁻

At cathode:   2 Li⁺   +   2e⁻  →  Li

Learn more about electrolysis, here:

brainly.com/question/12054569

#SPJ1

8 0
1 year ago
Which of the following statements about connecting paragraphs is correct?
Reika [66]
B.

And maybe put your question in the English/Literature tag next time lol
4 0
3 years ago
Read 2 more answers
If you have 1.1 moles of magnesium nitrate then how many grams is that
marysya [2.9K]

Answer: 162.8 grams

Explanation:

Magnesium nitrate has a chemical formula of Mg(NO3)2.

Given that:

Number of moles of Mg(NO3)2 = 1.1 moles

Mass in grams of Mg(NO3)2 = ?

For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g

Mg(NO3)2 = 24g + (14g + 16gx3) x 2

= 24g + (14g + 48g) x 2

= 24g + (62g) x 2

= 24g + 124g

= 148g/mol

Now, apply the formula:

Number of moles = Mass in grams / molar mass

1.1 moles = Mass / 148g/mol

Mass = 1.1 moles x 148g/mol

Mass = 162.8 grams

Thus, there are 162.8 grams of magnesium nitrate.

3 0
3 years ago
Naphthalene, commonly found in moth balls, is composed of 93.7% carbon and 6.3% hydrogen. The molar mass of naphthalene is 128 g
Vikki [24]

Answer:

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

Explanation:

Centesimal composition means that in 100 g of compound we have x g of the element. Therefore in 100 g of naphthalene we have:

93.7 g of C

6.3 g of H

Let's make a rule of three:

In 100 g of naphthalene we have 93.7 g of C  and 6.3 g of H

In 128 g of naphthalene we would have:

128 . 93.7 / 100 = 120 g of C

128.  6.3 / 100 = 8 g of H

We convert the mass to moles, by molar mass:

120 g . 1mol / 12 g = 10 moles C

8 g . 1mol/ 1g = 8 moles H

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

(The sub-index of each element is divided by the largest possible number)

6 0
3 years ago
Read 2 more answers
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