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kow [346]
3 years ago
11

The chaparral is characterized as a _________________ biome with _________________ , dry summers and mild, rainy winters, making

it vulnerable to infrequent _________________ in late summer and fall. Most chaparral biomes occur in _________________ and the Mediterranean. please help fast due in 20 minutes
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

temperate, hot, degradation, California

Explanation:

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Which state of matter has a constant volume, but changes shape?\?
never [62]
Liquids stays the same volume but the bonds are spaced out enough that it can take the shape of whatever container it’s in.
8 0
3 years ago
Calculate the volume of the gas, in liters, if 1.35 mol
Alina [70]

Answer:

22.8 L

Explanation:

Step 1: Given data

  • Moles of the gas (n): 1.35 mol
  • Pressure of the gas (P): 1.30 atm
  • Temperature (T): -6°C
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15 = -6 + 273.15 = 267 K

Step 3: Calculate the volume of the gas

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 1.35 mol × (0.0821 atm.L/mol.K) × 267 K / 1.30 atm

V = 22.8 L

7 0
4 years ago
Arjun placed a salt cube in a cup of water. He wonders whether stirring the water will make the salt cube
Ilya [14]

Explanation:

Yes...the molecules would get warmer has they collide into each Other...

8 0
3 years ago
What is the boiling point of cyclohexane at 620 mm hg?
Alchen [17]

The right answer is 271.78 degrees for cyclohexane.

For each liquid there is a precise relationship between pressure and boiling temperature, we can define the boiling temperature as the moment when the first bubble of vapor appears on the surface of a liquid.

8 0
3 years ago
Find the theoretical oxygen demand for the
never [62]

Answer:

a) 213.3 mg/L

b) 62.61 mg/L

c) 0.0225 mg/L

Explanation:

Theoretical oxygen demand (ThOD)is essentially the amount of oxygen required for the complete degradation of a given compound into the final oxidized products

a) Given:

Concentration of acetic acid,[CH3COOH] = 200 mg/L

CH3COOH + 2O2 \rightarrow 2CO2 + 2H2O

ThOD = \frac{mass\ O2}{mass\ CH3COOH} * conc. CH3COOH

Based on the reaction stoichiometry:

mass of CH3COOH = 60 g

mass of O2= 2(32) = 64 g

ThOD = \frac{64 g}{60 g} * 200mg/L = 213.3 mg/L

b) Given:

Concentration of ethanol, [C2H5OH] = 30 mg/L

C2H5OH + 3O2 \rightarrow 2CO2 + 3H2O

ThOD = \frac{mass\ O2}{mass\ C2H5OH} * conc. C2H5OH

Based on the reaction stoichiometry:

mass of C2H5OH = 46 g

mass of O2= 3(32) = 96 g

ThOD = \frac{96 g}{46 g} * 30mg/L = 62.61 mg/L

c) Given:

Concentration of sucrose, [C12H22O11] = 50 mg/L

C12H22O11 + 12O2 \rightarrow 12CO2 + 11H2O

ThOD = \frac{mass\ O2}{mass\ C22H22O11} * conc. C12H22O11

Based on the reaction stoichiometry:

mass of C12H22O11 = 342 g

mass of O2= 12(32) = 384 g

ThOD = \frac{384 g}{342 g} * 50mg/L = 0.0225 mg/L

7 0
3 years ago
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