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wolverine [178]
3 years ago
12

In cucumbers, green skin (G) is dominant to striped skin (g). If a farmer crosses a heterozygous (hybrid) cucumber with a homozy

gous (purebred) striped cucumber, what will the offspring look like?
Chemistry
1 answer:
Elena L [17]3 years ago
8 0

Answer:

Half will be green and half will be striped

Explanation:

Given green skin (G) is dominant to striped skin (g).

Cucumber 1 : Heterozygous (Gg)

Cucumber 2 : Homozygous striped (gg)

When Gg X gg :

     G      g

g   Gg   gg

g   Gg   gg

Half of the offspring will have Gg genotype so they will be green. Other half will have gg genotype so they will be striped.

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Answer: Thomson

Explanation: It verified J. J. Thomson's work on the atomic structure.

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If 1. 3618 moles of AsF3 are allowed to react with 1. 0000 mole of C2Cl6, what would be the theoretical yield of AsCl3, in moles
VARVARA [1.3K]

Answer:

AsF3:C2CI6

4:3

1.3618 moles: 1.02135 moles(1.3618÷4×3)

C2CI6 is the limting reagent

So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)

or

Balanced equation

4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4

Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.

Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.

Explanation:

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2 years ago
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AHYPOTHISES IS A GUESS

Explanation:

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Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1
anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

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m_{O_2}=8.65g-8.00g=0.65g

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