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wolverine [178]
3 years ago
12

In cucumbers, green skin (G) is dominant to striped skin (g). If a farmer crosses a heterozygous (hybrid) cucumber with a homozy

gous (purebred) striped cucumber, what will the offspring look like?
Chemistry
1 answer:
Elena L [17]3 years ago
8 0

Answer:

Half will be green and half will be striped

Explanation:

Given green skin (G) is dominant to striped skin (g).

Cucumber 1 : Heterozygous (Gg)

Cucumber 2 : Homozygous striped (gg)

When Gg X gg :

     G      g

g   Gg   gg

g   Gg   gg

Half of the offspring will have Gg genotype so they will be green. Other half will have gg genotype so they will be striped.

You might be interested in
10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C
Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

Q=mc\Delte T

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c =  0.385 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c =  0.903 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c =  2.42 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c =  4.18J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c =  0.128 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0
4 years ago
5, the answer is not c , pleaser answer
Tom [10]
I pretty sure that it’s b
6 0
3 years ago
What are 4 examples of sediment that may become sedimentary rock
jeka94
Rockkkkkkkkkkkkkkkkskskskksks
7 0
4 years ago
The pressure of a 250 mL sample of gas is 105 kPa. What would be the pressure if the volume were increased to 375 ml?
Arte-miy333 [17]

Answer:

<h2>The answer is 70 kPa</h2>

Explanation:

In order to find the pressure if the volume were increased to 375 ml we use Boyle's law

That's

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question

P1 = 105 kPa = 105 , 000 Pa

V1 = 250 mL

V2 = 375 mL

So we have

P_2 =  \frac{105000 \times 250}{375}  =  \frac{26250000}{375}  \\  = 70000

We have the final answer as

<h3>70 kPa</h3>

Hope this helps you

8 0
4 years ago
This diagram shows a ball rolling from left to right along a frictionless surface. In which sections will the ball be subjected
arlik [135]

Answer:

C.

Explanation:

Section 1 and section 4 are balanced.

6 0
3 years ago
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