Although the problem gives the value of b, it's really not needed.
Opposite sides of a parallelogram are congruent, so we just need to calculate: 2a + 2c = P
Plug the given values in:
2 * 7.6 + 2 * 14.6 = 44.4 units, or choice (C).
The answer to this problem= 0
⇒6x + 2 + - 1 - 4x - 3 + - 2x + 2 = 0
⇒2 - 1 - 3 + 2 + 6x + -4x - 2x = 0
⇒1 - 3 + 2 + 6x + -4x - 2x = 0
⇒-2 + 2 + 6x + -4x + -2x = 0
⇒0 + 6x + -4x + -2x = 0
⇒6x - 4x - 2x = 0
⇒2x + -2x = 0
Combine like terms: 2x + -2x = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.
Problem-solving is the definition of the problem. Identify the cause of the problem. Identify, prioritize, and select alternative solutions. and solution implementation. problem-solving process. Troubleshooting resources.
The definition of a problem is something that needs to be resolved or an unpleasant or undesirable condition that needs to be corrected. An example problem is an algebraic equation. An example problem is when it's raining and you don't have an umbrella.
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Answer:
45 sq. units
Step-by-step explanation:
We can draw a segment from F to S, splitting this figure into a rectangle and a triangle.
The area of a rectangle is given by the formula A=lw, where l is the length and w is the width.
The width of this figure is the distance of FW; this is 2. The length of this figure is the distance of WC; this is 9. This makes the area of the rectangle A=2(9) = 18 sq. units.
The area of a triangle is given by the formula A=1/2(b)(h), where b is the base and h is the height.
The base of the triangle is given by the distance of FS; this is 9. The height of the triangle is given from N to segment FS; this is 6. This makes the area of the triangle A=1/2(6)(9) = 27 sq. units.
This makes the total area 18+27 = 45 sq. units.
The division of a polynomial is illustrated below.
<h3>What is a polynomial?</h3>
It should be noted that a polynomial simply means an expression that consist of variables which involves the operation of addition, subtraction, etc.
The way to divide the polynomial will be:
Set up the division problem.
Determine the first term of the quotient.
Multiply the answer by the divisor.
Write it below the like terms of the dividend.
Subtract the bottom binomial from the term above it.
Bring it down and repeat the steps until you reach the last term.
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