Question

what is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x 3y = –5?

Answer 1

Answer:

d on ed

Step-by-step explanation:

Answer 2

Line II 
2x+3y=-5
3y=-2x-5
y=$\frac{-2}{3} x- \frac{5}{3}$

Gradient m= $\frac{-2}{3}$
Gradient of line I will be;
$\frac{-2}{3} *m=-1$
m=$\frac{3}{2}$
Equation of line I;
y=mx+c
y=$\frac{3}{2} x+c$
Finding value of c by replacing for;
y=1
x=-6
1=$\frac{3}{2} *(-6)+c$
c=10
y=$\frac{3}{2} x+10$