I’m an experiment you are asked to react hydrolic acid with sodium hydroxide. When measuring the volume of the reactants, which
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Answer:
200 grams of NaOH are produced with the reaction of 5.00 moles of water
Explanation:
First of all you apply a rule of three to know the amount of moles of NaOH as follows: if 2 moles of water produce 2 moles of NaOH, 5 moles of water how many moles would they produce?
moles of NaOH= 5
Being:
- Na: 23 g/mole
- O: 16 g/mole
- H: 1 g/mole
the molar mass of NaOH is: 23 g/mole + 16 g/mole + 1 g/mole= 40 g/mole
Then a rule of three applies as follows: if in 1 mole there are 40 g of NaOH, in 5 moles how much mass is there?
mass= 200 g
<u><em>200 grams of NaOH are produced with the reaction of 5.00 moles of water</em></u>