Beth made the chart shown. Which headings best complete the chart?
1 answer:
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According to the statement
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid
<h3>What is neutralization?</h3>A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.
<h3>According to the given information:</h3>The equation of the neutralization reaction between H2SO4 and CaCO3.
CaCO3 + H2SO4 → CaSO4 + H2CO3
H2CO3 dissociate to water and carbon dioxide.
CaCO3 + H2SO4 → CaSO4 + H2O + CO2
Now solving for the mass of CaCO3 needed to neutralize the acid.
mass of CaCO3 = 9460 Kg H2SO4 ×
= 21284.56606
mass of CaCO3 = 2.12 x 10^4 lbs
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.
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Answer:
The answer to your question is 25.9 g of KCl
Explanation:
Data
Grams of KCl = ?
Volume = 0.75 l
Molarity = 1 M
Formula
Solve for number of moles
Substitution
Number of moles = 1 x 0.75
Simplification
Number of moles = 0.75 moles
Molecular mass KCl = 39 + 35.5 = 34.5
Use proportions to find the grams of KCl
34.5 g of KCl ---------------- 1 mol
x ---------------- 0.75 moles
x = (0.75 x 34.5) / 1
x = 25.9 g of KCl