Someone pls help me
1 answer:
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Answer:
(a)
(b)
(c)
Explanation:
Hello,
In this case, given the molality in mol/L, we can compute the required units of concentration assuming a 1-L solution of acetonitrile and lithium bromide that has 1.80 moles of lithium bromide:
(a) For the molality, we first compute the grams of lithium bromide in 1.80 moles by using its molar mass:
Next, we compute the mass of the solution:
Then, the mass of the solvent (acetonitrile) in kg:
Finally, the molality:
(b) For the mole fraction, we first compute the moles of solvent (acetonitrile):
Then, the mole fraction of lithium bromide:
(c) Finally, the mass percentage with the previously computed masses:
Regards.
Answer:
The space that NH3 occupies is 1,205L
Explanation:
Using the ideal gas law we can find the volume of the gas
Where:
- P is the pressure of the gas in Torr
- V is the volume of the gas in Liters
- n are the moles of gas
- T is the temperature of the gas in Kelvin
- R is the gas constant (62,36 L.Torr/K.mol)
First, we convert the temperature to kelvin, and find the moles of gas using the mass and molecular weight of NH3
T(K)= °C + 273,15= 40 + 273= 313K
Now we find the volume with the ideal gas law