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ryzh [129]
3 years ago
5

A sample of water vapor condenses to form liquid water. What change in water

Chemistry
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

Condensation is the process of water vapor condensing into liquid water.

Explanation:

"Water condenses on a can of cold soda. Water vapor in the air reaches its dew point as it cools in the air around the can, forming liquid drops of water. Condensation is the process where water vapor becomes liquid. It is the reverse of evaporation, where liquid water becomes a vapor." -National Geographic"

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from the equation 2PbO + C = 2Pb + CO2, detemine which one is reactant is oxidised and which is reduced.​
ss7ja [257]

Answer:

Explanation:

C is oxidised because C up to C+4

PbO is reduced because PbO from Pb2+ down to Pb0

6 0
3 years ago
Read 2 more answers
When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
Pavel [41]
NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
6 0
3 years ago
Help i don't know how to find the percentage yield in stoichiometry!
Harrizon [31]
Sorry I honestly have no idea I just want my points
3 0
3 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
3 years ago
Fill in the coefficients that will balance the following reaction: a0Zn + a1Fe(NO3)2 → a2ZnNO3 + a3Fe
kramer
Zn + Fe(NO3)2 -> Zn(NO3)2 + Fe
4 0
3 years ago
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